Answer:
6
Step-by-step explanation:
(6*200)+(10*60)=1800
(6*50)+(10*10)=400
Answer:
First option: 
Second option: 
Fourth option: 
Step-by-step explanation:
Rewrite each equation in the form 
and then use the Discriminant formula for each equation. This is:
1) For :
Then:
Since 
this equation has no real solutions, but has two complex solutions.
2) For :
Then:
Since this equation has no real solutions, but has two complex solutions.
3) For 
:
Then:
Since 
this equation has one real solution.
4) For :
Then:
Since , this equation has no real solutions, but has two complex solutions.
359, 357, 348, 347, 337, 347, 340, 335, 338, 348, 339, 356, 336, 358 a. median: 359 mode: 358 c. median: 347 mode: 347 AND 348 b
Elodia [21]
Answer:
Option C (Median: 347 and Mode: 347 and 348)
Step-by-step explanation:
Median is the middle point of the data and mode is the most repeated observation is the data. The first step involved in calculating the median it to list the observations in the ascending order. This gives:
335, 336, 337, 338, 339, 340, 347, 347, 348, 348, 356, 357, 358, 359
The second step is to identify the middle number (in case the observations are in odd numbers) or numbers (in case the observations are in even numbers) after the ascending order step has been done. It can be observed that the middle numbers in this data set are 347 and 347. Since there are two numbers, so their average will be the median of this data set. Therefore, the median is 347. It can be seen that maximum repetitions are 2 times for 347 and 348. So the mode is 347 and 348.
Therefore, Option C is the correct answer!!!
Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
