9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
2(3r+7)−(2+r)
Use distributive property:
6r + 14 - 2 - r
Simplify by combining like terms:
5r +12
Divide both sides of the inequality by 4 but don’t flip the symbol.
You only flip the inequality symbol if you divide by a negative number.
If you’re solving for x (which you are), you want to get x by itself. The only way to do that is to divide by 4.
It's the first one. y = 3x
proportional means they are just some multiple of the other.
Answer:
Step-by-step explanation:
HOPE IT HELPS U MATE
