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lisabon 2012 [21]
3 years ago
15

Use the vertical line test to determine if the graph is a function or not a function. On a coordinate plane, a graph decreases t

o a minimum point, and then increases. On a coordinate plane, a graph increases to a maximum, decreases to a minimum, increases to the maximum, and decreases again to the minimum. On a coordinate plane, a graph decreases to the right, then decreases to the left, then decreases to the right.
Mathematics
2 answers:
Goryan [66]3 years ago
5 0

Answer:

bro could u help me with mine ill try to help u

larisa86 [58]3 years ago
4 0

function,function, not a function

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6 There are 10 lanes in the bowling alley where Harold bowls. He wants to make a
zimovet [89]

Answer:

The width of 10 lanes would be a total of  10 centimeters , 1 cm for each lane on his drawing.

Step-by-step explanation:

The scale he uses is

15 ft= 3 cm

1 feet = 3/15 cm

1 cm= 15ft/3= 5 ft

One lane = 60 ft long and 5 ft wide

In centimeters it would be 60 ft / 5ft = 12 cm long and 5 ft/5ft= 1 cm wide

The width of 1 lane is 1 cm .

The width of 10 lanes would be a total of  10 centimeters , 1 cm for each lane on his drawing.

3 0
3 years ago
Choose Yes or No to tell whether each value of p is a solution for this inequality.
blsea [12.9K]
No
THE P IS SOMETHING U NEED TO PLUG IN
6 0
4 years ago
What is the difference?<br> X/x2+3x+2 - 1/(X+ 2)(x+1)
Anarel [89]

Answer:

D

Step-by-step explanation:

\[\frac{x}{x^{2} +3x+2} -\frac{1}{(x+2)(x+1)} =\frac{x}{x^2+3x+2} -\frac{1}{x(x+1)+2(x+1)} =\frac{x}{x^{2}+3x+2 } -\frac{1}{x^{2} +2x+x+2} =\frac{x}{x^{2} +3x+2} -\frac{1}{x^{2} +3x+2} =\frac{x-1}{x^{2} +3x+2} \]

5 0
4 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ivanzaharov [21]

Answer: The value of x is -5 and the value of y is 5.

Explanation:

The slope of the line is \frac{2}{3} and the point is (-2,5) from which the line line is passing.

If a line is passing through the point (x_1,y_1) with slope m, the the equation of line is,

y-y_1=m(x-x_1)

y-5=\frac{2}{3}(x+2)

3y-15=2x+4

3y-2x=19    ..... (1)

It is given that the point A(x,3) and B(-2,y) lies on the line. It means it satisfies the equation of the line.

Put y=3 in equation (1).

3(3)-2x=19

-2x=10

x=-5

The value of x is -5.

Put x=-2.

3y-2(-2)=19

3y+4=19

3y=15

y=5

The value of y is 5.

3 0
4 years ago
Read 2 more answers
Help needed please and thank you
Dovator [93]
A OK this was hard very hard
4 0
3 years ago
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