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iren [92.7K]
3 years ago
15

Find the percent increase or decrease to the nearest percent. From 14 books to 40 books From 72 points to 50 points

Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Answer:

44% increase

Step-by-step explanation:

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Elen planned to read a book of 40 pages in two days. On the first day, she read 4 hours reading 7 pages per hour. On the second
amm1812

Ok so 7 times 4 is 28 so she read 28 the first day. For the second day since 40-28= 12, 12 divided by 2 is 6. So she read 6 pages per hour.

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3 years ago
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Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
ss7ja [257]

Answer:

\frac{3}{4} chance of landing on a factor of 24

Step-by-step explanation:

There are 8 sections on the spinner.

The factors of 24 are :

1,2,3,4,6,8,12,24

Only 1,2,3,4,6,8 are expressed on the spinner.

There are \frac{6}{8} or \frac{3}{4} chance you will land on a factor of 24.

7 0
3 years ago
4+3[-4(-4)+1]<br>How do we evaluate this
Elena-2011 [213]
4 + 3[ - 4( - 4) + 1]
4 + 3(( - 4)(- 4) + 1)
4 + 3(16 + 1)
4 + (3)(17)
4 + 51
Answer: 55




Hope that helps!!!
7 0
3 years ago
Please help<br><br> No links as they don’t work<br><br> Will mark brainliest
MariettaO [177]
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6 0
2 years ago
Use the matrix tool to solve the system of equations. Choose the correct ordered pair.3x + 5y = 42 6x + 5y = 54
kobusy [5.1K]
Solutions  

In Matrix we use initially based on systems of linear equations.The matrix method is similar to the method of Elimination as but is a lot cleaner than the elimination method.Solving systems of equations by Matrix Method involves expressing the system of equations in form of a matrix and then reducing that matrix into what is known as Row Echelon Form.<span> 

Calculations 

</span>⇒ <span>Rewrite the linear equations above as a matrix 
</span>
\left[\begin{array}{ccc}3&5&42\\6&5&54\\\end{array}\right] 

⇒  Apply to Row₂ : Row₂ - 2 <span>Row₁ 
</span>
\left[\begin{array}{ccc}3&5&42\\0&-5&-30\\\end{array}\right] 

⇒ <span>Simplify rows
</span>
\left[\begin{array}{ccc}3&5&42\\0&1&6\\\end{array}\right] 

Note: The matrix is now in echelon form.
<span>The steps below are for back substitution. 
</span>
⇒ Apply to Row₁<span> : Row</span>₁<span> - </span>5 Row₂ 

\left[\begin{array}{ccc}3&0&12\\0&1&6\\\end{array}\right] 

⇒ <span>Simplify rows 
</span>
\left[\begin{array}{ccc}1&0&4\\0&1&6\\\end{array}\right] 

⇒ <span>Therefore, 
</span>
x=4&#10;&#10;y = 6
<span> 

 
</span>

5 0
3 years ago
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