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3 years ago

HELP!! VERY TIME TIME SENSITIVE

Mathematics

1 answer:

guapka [62]3 years ago

3 0

Answer:

B is your correct answer

Step-by-step explanation:

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Write each fraction as a percent 4/100

nadezda [96]

Answer:

4%is the answer you are looking for

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3 years ago

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Isabella has 21/4 cups of granola and adds 11/2 cups of raisins she then adds 11/4 cups of almonds to the mix she divide the mix

lesya692 [45]

Idk sorry hope u find the answer

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

Find the exact value of tan A in simplest radical form.

spin [16.1K]

Answer:

$tan(A) = \frac{2\sqrt{15}}{11}$

Step-by-step explanation:

Given:

Right ∆ABC

AB = 61

BC = 60

AC = 11

Required:

Value of tan A in radical form

SOLUTION:

$tan(A) = \frac{opposite}{adjacent}$

Opposite = 60

Adjacent = 11

$tan(A) = \frac{60}{11}$

$tan(A) = \frac{\sqrt{4*15}}{11}$

$tan(A) = \frac{2\sqrt{15}}{11}$

6 0

3 years ago

7 1/7 divided by 5 1/5

vladimir1956 [14]

Well first turn 1/7 and 1/5 into decimals which would be .142857 and .2 Add those to 7 and 5 to get 7.143 (I rounded this to the nearest thousandth) and 5.2 Divide those and you get 1.374

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3 years ago