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Hunter-Best [27]
3 years ago
14

Identify the parent function related to the given function. Choose the correct answer from the choices below:

Mathematics
1 answer:
dedylja [7]3 years ago
7 0

Answer:

thats what I could help with its in fact really help full

You might be interested in
Which is the prime factorization of 40?
Lana71 [14]

Hey there!

Which is the prime factorization of 40?


Option A.

2 * 5

= 2 + 2 + 2 + 2 + 2

= 4 + 4 + 2

= 8 + 2

= 10


Option B.

2^3 * 5

= 2 * 2 * 2 * 5

= 4 * 2 * 5

= 8 * 5

= 40


Option C.

2 * 53

= 53 * 2

= 53 + 53

= 106


2 * 3 * 5

= 6 * 5

= 6 + 6 + 6 + 6 + 6

= 12 + 12 + 6

= 24 + 6

= 30


Therefore, your answer is:

Option B. 2^3 * 5


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

4 0
2 years ago
Please help me jdjdjd
jeyben [28]
If you add Hillary to the friend count, that's 24. So there are 16 boys and 8 girls
8 0
3 years ago
Ann opened a new savings account with an initial deposit of $250. Which combination will result in a zero in balance in Ann's ac
Blababa [14]
C.  (10x3)10 - (27.5x2)10 = 0
8 0
3 years ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
10kg 20kg 24kg ?kg plz answer this for me
luda_lava [24]

Answer:

27KG

Step-by-step explanation:

Mouse- M , Cat - C, Dog - D

M + C = 10 ----- (1)

M + D = 20 -------(2)

C + D = 24 --------(3)

(1) - (2) => C - D = -10 ---- (4)

(3) + (4) => 2C = 14

                => C = 7

Substitute C in (1)  => M + 7 = 10

                            => M = 3

Substitute M in (2) => 3 + D = 20

                            => D = 17

Therefore C + M + D = 7 + 3 + 17 = 27KG

3 0
3 years ago
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