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oee [108]
3 years ago
8

What is 80%of 1,60will mark brainliest​

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

Step-by-step explanation:

Converte 80% into a decimal (devide it by 100) = 0.8

Then multiply 0.8 by 1.60 = 1.28 (final result)

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Three microcontrollers are needed to operate a specific type of robot. Such a robot stops working whenever one or more microcont
Xelga [282]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

The robot will work only if all the micro controller works on the competition day.

The probability of the micro controller's failing is \frac{1}{2}.

The probability of the micro controller's success is \frac{1}{2}.

Hence, the required probability is \frac{1}{2} \times \frac{1}{2}  \times \frac{1}{2} = \frac{1}{8}.

(b)

From the three micro controller, one can be chosen in ^3C_1 = 3 ways.

The probability here is \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}\times3 = \frac{3}{8}.

(c)

If from the four micro controllers, one fails, then also they can manage to make  the robot work.

From the 4, 1 can be chosen in 4 ways.

This one can either work properly or not.

<u>If it works properly, then the probability of other 3 will work properly is</u> (\frac{1}{2} )^4 = \frac{1}{16}.

<u>If the chosen one does not work properly, then the probability  of other 3 will work properly is</u> (\frac{1}{2} )^4 = \frac{1}{16}.

The required probability is 3(\frac{1}{16} + \frac{1}{16}  ) = \frac{3}{8}.

(d)

In this case there are total 6 micro controllers.

From these 6 controllers, 3 can be chosen as ^6C_3 = \frac{6!}{3!\times3!} = 20ways.

The probability that the team is able to reshuffle the micro controllers to make one robot work is 20\times(\frac{1}{2} )^6 = \frac{5}{16}.

3 0
4 years ago
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