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prisoha [69]
3 years ago
9

Use the impulse-momentum theorem to find how long a stone falling straight down takes to increase its speed from 5.6 m/s to 10.6

m/s . Express your answer in seconds.
Physics
1 answer:
Nezavi [6.7K]3 years ago
7 0

As stated, the impulse and momentum definitions will be used to later find the value of time through the force of gravity. According to the theory, the impulse formula is given as,

I = F\Delta t

Here,

F = Force

\Delta t = Change in time

Now using the impulse theorem we have that,

Change in Impulse = Change in momentum

F\Delta t = \Delta p (1)

The change in momentum is given as

\Delta p = p_f -p_i

\Delta p = (-10.6)-(-5.6)

\Delta p = -5m/s

The force due to gravity is through the Newton's second law

F_g = -mg

Here,

m = mass

g = Acceleration due to gravity

Substitute the value in (1)

-mgt = -5m/s

9.8t = 4.9

t = \frac{5}{9.8}

t = 0.51s

Therefore it will take 0.51s.

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Contact lenses are designed to be gas permeable in order to allow oxygen to diffuse to the eye. If the edge of a contact lens is
guapka [62]

Answer: A

The diffusion time through the edge is double the diffusion time through the center.

Explanation:

Only the diffusion coefficient, thickness, surface area, distance affects the time it takes a gas such as oxygen to diffuse a given in a medium. The Diffusion time increases with the square of diffusion distance  Also, the Increased surface area increases the rate of diffusion or the diffusion time, whereas a thicker membrane reduces the rate of diffusion or time it takes the gas to be permeable. Also, The greater the distance that a substance must travel, the slower the rate of diffusion The diffusion coefficient determines the time it takes a gas to diffuse. Also the Diffusion time is inversely proportional to the diffusion coefficient.

Now, If the edge of a contact lens is double the thickness of the central portion of the lens, then it will take more time for the gas to diffuse through the thicker portion. since its edge is double the central position, then the diffusion time will also be doubled. So Option A is the best answer-

The diffusion time through the edge is double the diffusion time through the center.

6 0
4 years ago
A well-insulated electric water heater warms 131 kg of water from 20.0°C to 51.0°C in 31.0 min. Find the resistance (in Ω) of it
Nookie1986 [14]

Answer:

Explanation:

Heat required to warm the water from 20 degree to 51 degree

= mct

= 131 x 4150 x ( 51 - 20 )

= 16853150 J

Power of heating element

= v² /R

Heat generated in 31 min

= (v² / r ) x 31 x 60 = 16853150

r = (240 x 240 x 31 x 60) / 16853150

6.35 ohm

In this case heat required will change so time will also change

Heat required =

131 x 4150 x ( 100-51  )

= 26638850 J

If time required be t hour

Energy consumed

Power x time

=  (v² / r ) x t  x 60 = 26638850

t  = 26638850 x 6.35 / (240 x 240 x 60 )

= 48.95 h

Heat required to evaporate water at 100 degree

= mass x latent heat

= 131 x 2260000

= 296060000 J

Total heat required

= 296060000 + 26638850 + 16853150

= 339552000 J

time required = 339552000 x 6.35 / (240 x 240 x 60 )

= 623.88 h .

3 0
3 years ago
An electric heater used to boil small amounts of water consists of a 15-Ω coil that is immersed directly in the water. It operat
Allisa [31]

Answer:

t = 1120 seconds

Explanation:

Law of Conservation of Energy: It states that energy can neither be created or destroyed but it can be transformed from one form to another

The heater converts electric energy to heat energy.

According to the law of conservation of Energy,

Heat supplied by the heater = heat gained by the water.

Heat supplied by the heater = (V²/R)t, Where V = voltage, R = Resistance, t = Time.

Heat gained by the water = cm(θ₂ -θ₁)

Where c = specific heat capacity of water, m = mass of water, θ₂= final temperature of water, θ₁= initial temperature of water.

∴ (V²/R)t =  cm(θ₂ -θ₁)

Making  t the subject of the equation,

t =  cm(θ₂ -θ₁) ×R/V²

Where c= 4200 Jkg/K, m=0.80 kg, R = 15 Ω, V = 60 V, θ₁= 20°C, θ₂ = the normal boiling point of water = 100°C

∴ t = (4200×0.8)(100 -20)×15/60²

t = (3360×80×15)/3600

t = 4032000/3600 = 1120 seconds

∴  The time required by the heater to raise the temperature of water to normal boiling point is 1120 seconds.

3 0
3 years ago
Show that a light ray that strikes two mutually perpendicular reflecting surfaces is reflected back exactly parallel to the dire
DedPeter [7]

Take a look at the attachment below. As you can see, the figure demonstrates a 90 degree angle such that the surfaces are perpendicular, and hence are independent of the angle of incidence. You could say that this forms a part of a parallelogram -

3 0
3 years ago
A 500 gram piece of metal has a volume of 2.75cm^3. What is its density?
olga_2 [115]

Answer:

mass= 500 grams

volume= 2.75 cm^3

density= 181.818182 g/cm^3

Explanation:

density is mass divided by volume so your answer is 181.818..

3 0
3 years ago
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