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2 years ago

What is the value of c ?

Mathematics

2 answers:

nadezda [96]2 years ago

7 0

Answer:

c = 35°

Step-by-step explanation:

Step 1:

c + 57° + 88° = 180° Equation

Step 2:

c + 145° = 180° Add

Answer:

c = 35°

Hope This Helps :)

Andrews [41]2 years ago

6 0

You add 88+57 and get 145. a straight line is 180 degrees so you would subtract 180-145 and get 35. the answer is 35.

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Casey wants to buy a gym membership. Gym A has a $150 joining fee and costs $35 per month. Gym B has no joining fee and costs $6

MariettaO [177]

Answer:

Step-by-step explanation:

Gym A has a $150 joining fee and costs $35 per month.

Assuming that Casey wants to attend for x months, the cost of using gym A will be

150 + 35 times x months. It becomes

150 + 35x

Gym B has no joining fee and costs $60 per month.

Again, assuming that Casey wants to attend for x months, the cost of using gym B will be

60 × x months = 60x

A) To determine the number of months that it will both gym memberships to be the same, we will equate them.

150 + 35x = 60x

60x - 35x = 150

25x = 150

x = 150/25 = 6

It will take 6 months for both gym memberships to be the same.

B) If Casey plans to only go to the gym for 5 months,

Plan A will cost 150 + 35×5 = $325

Plan B will cost 60 × 5 = $300

Plan B will be cheaper

6 0

3 years ago

Hi, am I supposed to find the stationary points of the f(x) and g(x) then use the distance formula to solve for the final answer

nikdorinn [45]

9514 1404 393

Answer:

maximum difference is 38 at x = -3

Step-by-step explanation:

This is nicely solved by a graphing calculator, which can plot the difference between the functions. The attached shows the maximum difference on the given interval is 38 at x = -3.

Ordinarily, the distance between curves is measured vertically. Here that means you're interested in finding the stationary points of the difference between the functions, along with that difference at the ends of the interval. The maximum difference magnitude is what you're interested in.

h(x) = g(x) -f(x) = (2x³ +5x² -15x) -(x³ +3x² -2) = x³ +2x² -15x +2

Then the derivative is ...

h'(x) = 3x² +4x -15 = (x +3)(3x -5)

This has zeros (stationary points) at x = -3 and x = 5/3. The values of h(x) of concern are those at x=-5, -3, 5/3, 3. These are shown in the attached table.

The maximum difference between f(x) and g(x) is 38 at x = -3.