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goldfiish [28.3K]
3 years ago
9

Conduct a hypothesis test to test the hypothesis that cloud seeding with silver nitrate increases rainfall. Use significance lev

el 0.1. Based on what you observed in answering the previous question, are you confident that this is a valid test? If not, what assumptions are violated?
Do I use the one sample t-test, two sample t-test, or the paired t-test?
Mathematics
1 answer:
masya89 [10]3 years ago
6 0

Answer:

Paired t-test

Step-by-step explanation:

paired t–test is used  when there is one measurement variable and two nominal variables. The most common design is that one nominal variable represents individual organisms, while the other is "before" and "after" some treatment.

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Please help asap! Ty!
NeX [460]

Area of the two side triangles:  10 and 10 = 20

A = 1/2 bh

A = (10*2)/2 = 10

Area of rectangle:

A = l x w

A = 10 * 9

A = 90

90 + 20 = 110

4 0
3 years ago
PLS HELP Find the value of x in the triangle shown below.
Alexxx [7]

Answer:

the answer is 20

Step-by-step explanation:

use the pythagorean theorem

1] 12 x 12 = 144

2] 16 x 16 = 256

3] 144 +256= 400

4] find square root of 400 which is equal to 20

4 0
3 years ago
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Destini has $64 to spend on a new game. If she spends 5/8 of her money on the
Mamont248 [21]
I’m not sure try using fraction calculator it helps me a lot I’m sorry I didn’t help
8 0
3 years ago
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Mr. Wilson's desk drawer contains 4 black, 3 blue, and 3 red pens. If he selects one pen a random, what is the probability that
gtnhenbr [62]
<h3>Answer:  3/5</h3>

Work Shown:

3 blue + 3 red = 6 pens that are either blue or red

4 black + 3 blue + 3 red = 10 pens total

6/10 = 3/5 is the probability of selecting either blue or red

3/5 = 0.60 = 60%

3 0
3 years ago
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
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