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gregori [183]
3 years ago
12

Find the value of x in the triangle. SU RV

Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

Answer:

x = 8

Step-by-step explanation:

Δ TSU and Δ TRV are similar , thus the ratios of corresponding sides are equal, that is

\frac{TS}{TR} = \frac{TU}{TV} , substitute values

\frac{x}{x+16} = \frac{5}{15} = \frac{1}{3} ( cross- multiply )

3x = x + 16 ( subtract x from both sides )

2x = 16 ( divide both sides by 2 )

x = 8

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Answer:

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Step-by-step explanation:

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Kaitlin collected donations for a local animal shelter. She collected a total of $11 on Friday. She collected 7 times that amoun
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a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be don
Veronika [31]

Wow !

OK.  The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
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-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8.  For each of these . . .
The third one can be any one of the remaining 7.  For each of these . . .
The fourth one can be any one of the remaining 6.  For each of these . . .
The fifth one can be any one of the remaining 5.  For each of these . . .
The sixth one can be any one of the remaining 4.  For each of these . . .
The seventh one can be any one of the remaining 3.  For each of these . . .
The eighth one can be either of the remaining 2.  For each of these . . .
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     The total number of possible line-ups is 

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For each possible line-up, the teacher and the difficult student can sit

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-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
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So the total total number of ways to do this is

           (362,880) x (10)  =  3,628,800  ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

4 0
3 years ago
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