Direct variation is of the form y=kx, where k is the constant of variation. It is "direct" because as x increases/decreases so does y in the same magnitude.
y=kx, In this case the dependent variable y, is miles and the independent variable x, is gallons. We are told that the car gets 28mi/gal so
y=28x
The answer is c. we add 4x^4+x^4. then cancel the -x^2+x^2 and also the -x and x . so, we are left with the -1. that's why the answer is c
Answer:
<em>The probability that 10 or more students will live in campus housing is approximately 0.111%</em>
Step-by-step explanation:
<u>Binomial distribution formula:</u>
<em>If the probability of success is
, then the probability of
successes out of
trials will be:
</em>
26% of college students live in campus housing. So here, 
A random sample of 15 college students is selected. So, 
Now, "10 or more students" means 10 or 11 or 12 or 13 or 14 or 15 students. That means, 
Thus, the probability that 10 or more students will live in campus housing will be........
![[^1^5C_{10}(0.26)^1^0(1-0.26)^5]+[^1^5C_{11}(0.26)^1^1(1-0.26)^4]+[^1^5C_{12}(0.26)^1^2(1-0.26)^3]+[^1^5C_{13}(0.26)^1^3(1-0.26)^2]+[^1^5C_{14}(0.26)^1^4(1-0.26)^1]+[^1^5C_{15}(0.26)^1^5(1-0.26)^0]\\ \\ = 0.00094...+0.00015...+0.00001...+ 0.0000014...+ 0.000000071...+0.0000000016...\\ \\ =0.00111002... =0.111002...\% \approx 0.111\%](https://tex.z-dn.net/?f=%5B%5E1%5E5C_%7B10%7D%280.26%29%5E1%5E0%281-0.26%29%5E5%5D%2B%5B%5E1%5E5C_%7B11%7D%280.26%29%5E1%5E1%281-0.26%29%5E4%5D%2B%5B%5E1%5E5C_%7B12%7D%280.26%29%5E1%5E2%281-0.26%29%5E3%5D%2B%5B%5E1%5E5C_%7B13%7D%280.26%29%5E1%5E3%281-0.26%29%5E2%5D%2B%5B%5E1%5E5C_%7B14%7D%280.26%29%5E1%5E4%281-0.26%29%5E1%5D%2B%5B%5E1%5E5C_%7B15%7D%280.26%29%5E1%5E5%281-0.26%29%5E0%5D%5C%5C%20%5C%5C%20%3D%200.00094...%2B0.00015...%2B0.00001...%2B%200.0000014...%2B%200.000000071...%2B0.0000000016...%5C%5C%20%5C%5C%20%3D0.00111002...%20%3D0.111002...%5C%25%20%5Capprox%200.111%5C%25)
Answer:
The answer is 8
Step-by-step explanation:
2 + 6 = 8
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