Answer:
tanA/2.
Step-by-step explanation:
some trigonometric properties:
* tanA = sinA/cosA
* secA = 1/cosA
* cscA = 1/sinA
* cotA = cosA/sinA
1/sinA - cotA
1/sinA - cosA/sinA
1 - cosA / sinA
.... 1 - cosR / sinR = tan(R/2)
1 - cosA / sinA
= tanA/2.
Answer:
Step-by-step explanation:
![y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\ \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}](https://tex.z-dn.net/?f=y%20%3D%20sin%28xy%29%5C%5C%5Cfrac%7Bd%7D%7Bdx%7Dy%3Dcos%28xy%29%28%5Cfrac%7Bd%7D%7Bdx%7D%28xy%29%29%5C%5C%20%20%5Cfrac%7Bd%7D%7Bdx%7Dy%20%3D%20cos%28xy%29%28y%20%2B%20x%2A%5Cfrac%7Bd%7D%7Bdx%7Dy%29%5C%5C%20write%20%5C%3A%20%5Cfrac%7Bd%7D%7Bdx%7Dy%20%5C%3A%20as%5C%3Ay%27%5C%5Cy%27%20%3D%20cos%28xy%29%28y%2Bxy%27%29%5C%5Cy%27%20%3D%20ycos%28xy%29%20%2B%20xy%27cos%28xy%29%20%5C%5Cy%27-xy%27cos%28xy%29%20%3D%20ycos%28xy%29%5C%5Cy%27%281-xcos%28xy%29%29%20%3D%20ycos%28xy%29%5C%5C%5C%5Cy%27%20%3D%20%5Cfrac%7Bycos%28xy%29%7D%7B1-xcos%28xy%29%7D)
If the side lengths are all 6 units, then the surface area and volume are the same
surface area = 6*s^2 = 6*6^2 = 216
volume = s^3 = 6^3 = 216
You can find this by solving s^3 = 6s^2 for s to get s = 0 or s = 6. The solution s = 0 is trivial so you can ignore it.
I don’t know this one either bro
4.5 and maybe 16-64. If they count -