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3 years ago

Which expression is equivalent to the given expression?

Mathematics

1 answer:

OlgaM077 [116]3 years ago

8 0

Answer:

16y-6

Step-by-step explanation:

(3y-4)(2y+7)+11y-9

5y+3+11y-9

16y-6

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If f(x) = [x] - 5, what is f(8.6)? a) 3 b) 4 c) 8 d) 9

NeTakaya

A is the answer to this question because if you plug in 8.6-5 it is approximately 3

6 0

3 years ago

Read 2 more answers

How do I solve this algebra two btw

pychu [463]

$\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}$

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

$\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill$

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2 years ago

√-1 factor completely without any 'i'

Tanzania [10]

Answer:

the root of -1 is -1

Step-by-step explanation:

When multiplied by itself, the root is typically a specified number of times gives a specified number or quantity. So -1 × -1 = -1

So there you go

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3 years ago

Find the volume of the Prism

taurus [48]

The answer is 60 boi

7 0

3 years ago

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Use the given root to find the remaining root of the function. Root: x = - 3 Function: f(x) = x ^ 2 + x - 6

ra1l [238]

Answer:

x = 2

Step-by-step explanation:

Since we know one root is -3, we know one factor of the equation is (x+3)

From there we can use the factor we know to factor the rest of the equation:

x^2 + x - 6 = (x+3) * ?

Since know -6 is just 3 * -2 and since 3-2 is 1,

(x+3)(x-2) = x^2 + x - 6

From there,

x - 2 = 0

x = 2

6 0

3 years ago