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3 years ago

Laney is 4 feet 8 inches tall. There are 2.54 centimeters in 1 inch. What is Laney’s height in centimeters

Mathematics

1 answer:

love history [14]3 years ago

6 0

Solve

Given: 2.54cm = 1 inch

To find: 4 feet 8 inches in centimeters

If 1 inch is 2.45cm,

Divide 2.45 by 1

Then multiply it by 4.8

Final answer: 146.3cm in nearest tenth.

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fgiga [73]

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Which of the following represents all solutions to the equation <br> 1/3x^2 +10 = 7

fredd [130]

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2 years ago

Read 2 more answers

A community had a population of 12,000 in 1985, which is increased to 20,000 in 2010. The saturation population is 80,000. Estim

ivann1987 [24]

Answer:

The right answer is :

(a) 23,200

(b) 24,514

(c) 22,926

Step-by-step explanation:

According to the question,

$P_1 = 12000$

$P_2 = 20000$

$P_{sat}=80000$

(a)

We know that the arithmetic growth formula will be:

⇒ $P=Pi+K\times t$ ...(1)

here,

⇒ $K=\frac{P_2-P_1}{\Delta t}$

$=\frac{20000-12000}{25}$

$=\frac{80000}{25}$

$=320$

On putting the values in equation (1), we get

⇒ $P_{2020}=20000+320\times 10$

$=23,200$

(b)

The geometric growth formula will be:

⇒ $P=ln(Pi)+K\times t$

here,

⇒ $K=\frac{lnP_2-lnP_1}{\Delta t}$

$=\frac{ln(20000)-ln(12000)}{25}$

By putting the values of general log, we get

hence,

⇒ $P_f=ln(20000)+0.0204\times 10$

$=10.107$

$P_{2020}=e^{10.107}$

$=24,514$

(c)

⇒ $P_f=P_{sat}-(P_{sat}-P_i)e^{-K\times t}$

or,

⇒ $K=-\frac{1}{\Delta t}ln(\frac{P_{sat}-P_2}{P_{sat}-P_1} )$

from here, we get

$=0.005$

hence,

⇒ $P_{2020}=80000-(80000-20000)e^{-0.005\times 10}$

$=80000-(60000)e^{-0.005\times 10}$

$=22,926$

5 0

3 years ago

What’s the answer for this one??

KIM [24]

Answer:

It is the second one.

Step-by-step explanation:

a and e are equal because they are mirrored. d and b are equal because they are on the same line and at the same point where the parallel lines go through. b and f are also mirrored. That leaves c and e which don't match.

6 0

3 years ago