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3 years ago

13

La banqueta que rodea un jardín rectangular es de 4 metros de ancho. El jardín tiene

1 answer:

mylen [45]3 years ago

3 0

Answer:

jbhbchbhvbbhcbrhfbcbhshshbhsvhbhv;b;rvbhbhcrbihcbhc

Step-by-step explanation:

You might be interested in

Can someone please help me with this???

Orlov [11]

The green square is 15 ft wide by 15 ft tall.

The area of one green square is 15 x 15 = 225 square feet.

There are 4 sides plus the base : 225 x 5 = 1125 square feet for the green part.

One triangle has a base 15 feet wide and a height of 9 feet.

The area for one triangle is 1/2 x 15 x 9 = 67.5 square feet.

There are 4 triangles: 67.5 x 4 = 270 square feet.

Total: 1125 + 270 = 1,395 square feet.

3 0

4 years ago

Solve for x in the equation x squared + 2 x + 1 = 17.

Papessa [141]

Answer:

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

Step-by-step explanation:

given equation

$x^2 +2x +1 = 17$

subtracting 17 from both sides

$x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\$

the solution for quadratic equation

$ax^2 + bx + c = 0$ is given by

x = $x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a$

________________________________

in our problem

a = 1

b = 2

c = -16

$x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4 + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x = ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\$

thus value of x is

$x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\$

3 0

3 years ago

A company's year-end data shows the following amounts. Current assets $65,000 Current liabilities $25,000 Net income $7,500 Net

lozanna [386]

The company's current ratio is 2.6.

<h3>What is the current ratio?</h3>

Current ratio is an example of a liquidity ratio. Liquidity ratios are financial ratios measure a firm's ability to honour its short terms obligations.

Current ratio = current asset /current liability

$65,000 / 25,000 = 2.6

To learn more about current ratio, please check: brainly.com/question/19579866

#SPJ1

4 0

2 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

4 0

4 years ago

What is the simplified form of the following expression? 7(3sqrt2x)-3(3sqrt16x)-3(3sqrt8x)

coldgirl [10]

Assignment: $\bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}$

<><><><><><><>

Answer: $\boxed{\bold{3\sqrt{2}x-36x}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Remove Parenthesis (a) = a

$\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}$

[ Step Two ] Simplify Equations

$\bold{7\cdot \:3\sqrt{2}x: \ 21\sqrt{2}x}$

$\bold{3\cdot \:3\sqrt{16}x: \ 36x}$

$\bold{3\cdot \:3\sqrt{8}x: \ 18\sqrt{2}x}$

[ Step Three ] Rewrite Equation

$\bold{21\sqrt{2}x-36x-18\sqrt{2}x}$

[ Step Four ] Add Similar Elements

$\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}$

[ Step Five ] Rewrite Equation

$\bold{3\sqrt{2}x-36x}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

7 0

3 years ago