9514 1404 393
Answer:
60, 57, 54, 51, ...
Step-by-step explanation:
The general term of an arithmetic sequence is ...
an = a1 +d(n -1)
We would like to find the first term (a1) and the common difference (d). We can use the two given terms to find these parameters.
a10 = 33 = a1 +d(10 -1)
a22 = -3 = a1 +d(22 -1)
Subtracting the first equation from the second, we get ...
(-3) -(33) = (a1 +21d) -(a1 +9d)
-36 = 12d
-3 = d
Using this value in the first equation, we can find a1.
33 = a1 +9(-3) = a1 -27
60 = a1 . . . . . . . . . . . . . . add 27 to both sides
So, our sequence has first term 60 and a common difference of -3.
The first 4 terms are ...
60, 57, 54, 51, ...
Step-by-step explanation:
you can use any value either in place of x or y to find the corresponding coordinate but if you want to find the x and y intercept you can desigate x as zero and find the y intercept and vice versa.
so to find x and y intercept
y=25x+3. to find x intercept designate y as zero
0=25x+3
-3=25x
x= -3/25. p( -3/25,0)
y=25x+3 to find y intercept designate x as zero
y=25(0)+3
y=3. p(0,3)
the above y and x intercept indicates the points that the line of equation pass through when drawn graphically.
The answer is B, or 2x + 3y - 5 = 0. This is because when you substitute both points in for x and y, you get the values of 0=0, which is true!
I think the it would be some like y-8
