Question

Please help and show work if you can​

Answer 1

Answer:

38. <1 = $38^{o}$, <2 = $32^{o}$, <3 = $110^{o}$

39. <1 = $71^{o}$, <2 = $28^{o}$, and <3 = $81^{o}$

Step-by-step explanation:

38. Sum of angles in a triangle = $180^{o}$

So that;

38 + 110 + <2 = $180^{o}$

148 + <2 = $180^{o}$

<2 = $180^{o}$ - 148

<2 = $32^{o}$

Thus,

<1 = $38^{o}$ (alternate angle principle)

<3 = $110^{o}$

Therefore;

<1 = $38^{o}$, <2 = $32^{o}$, <3 = $110^{o}$

39. <2 = $28^{o}$ (alternate angle principle)

So that;

sum of angles in a triangle = $180^{o}$

<1 + <2 + 81 = $180^{o}$

<1 + $28^{o}$ + 81 = $180^{o}$

<1 + 109 = $180^{o}$

<1 = $180^{o}$ - 109

   = $71^{o}$

<1 = $71^{o}$

<3 = $81^{o}$

<1 = $71^{o}$, <2 = $28^{o}$, and <3 = $81^{o}$