Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
Answer:
62,100
Step-by-step explanation:
Answer:
2
the answer is 2 coz it's like terms
Answer:
41
Step-by-step explanation:
Answer:
E: b/3+3
Step by step:
3 C= b
C + 3 = b/3 + 3 (Adding 3 to both sides)
Answer: E: b/3 + 3
Hope this helps
