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3 years ago

15

PLEASE HELPPP!!! i dont get tge question

1 answer:

alisha [4.7K]3 years ago

3 0

Answer:

it's a substitution because y was solved

Step-by-step explanation:

2x +2(3x-7)=10

you just replace the "y' by the solved y

then you solve parenthesis and continue the rest.

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Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

What is the length of the hypotenuse of a right triangle with legs that are 7 and 8 inches

Mrrafil [7]

B). 10.63
Because 7^2=49 and 8^2=64 then 49+64=113 then the square root of 113 is 10.63

5 0

3 years ago

Read 2 more answers

Determine if the events A and B are independent. Show all steps.

zmey [24]

<u><em></em></u>

Answer:

$P(A U B ) = \frac{13}{25}$

Step-by-step explanation:

<u><em>STEP:-1</em></u>

Given that events A and B are independent then

P(A ∩B ) = P(A) P(B)

Given that P(A) = 2/5 and P(B) = 1/5

<u><em>STEP:- 2</em></u>

P(A ∩B ) = P(A) P(B)

$P(A U B) = P(A) +P(B) - P(A n B )$

$P(A U B ) = P(A) +P(B) - P(A) P(B)$

<u><em>Step(iii):-</em></u>

<u><em></em></u> $P(A U B ) = \frac{2}{5} +\frac{1}{5} - \frac{2}{5} X \frac{1}{5}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{3}{5} - \frac{2}{5} X \frac{1}{5}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{3}{5} - \frac{2}{25}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{15-2}{25} = \frac{13}{25}$ <u><em></em></u>

<u><em /></u>

<u><em /></u>

4 0

2 years ago

Someone help please?

vodka [1.7K]

Answer:

-9 and -4

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Find the slope of the line passing through the points (2,-9) and )1,-3)

nignag [31]

Hi there!

$\large\boxed{\text{slope =} 6}$

We can calculate slope using the following formula:

$slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Plug in the corresponding points:

$slope = \frac{-9-(-3)}{2-1}$

Simplify:

$slope = \frac{-6}{1} = -6$

3 0

3 years ago

Read 2 more answers