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3 years ago

PLEASE HELPPP!!! i dont get tge question

Mathematics

1 answer:

alisha [4.7K]3 years ago

3 0

Answer:

it's a substitution because y was solved

Step-by-step explanation:

2x +2(3x-7)=10

you just replace the "y' by the solved y

then you solve parenthesis and continue the rest.

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What is an expression for the area of the shaded region? Simplify your answer.

Reptile [31]

Answer:

if it is put into a equation this would be it

2(x^2+6x+9) - (1.57)(x^2+6x+9)

Step-by-step explanation:

(x+3)(2x+6) - 1/2(3.14)(x+3)(x+3)

(2x^2+6x+6x+18) - 1/2(3.14)(x^2+3x+3x+9)

(2x^2+12x+18) - 1/2(3.14)(x^2+6x+9)

2(x^2+6x+9) - (1.57)(x^2+6x+9)

2(x^2+6x+9) is the rectangle at the bottom

(1.57)(x^2+6x+9) is the semicircle that is taking out of the shaded area

5 0

3 years ago

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

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3 years ago

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Dafna1 [17]

Answer:

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Step-by-step explanation:

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