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Stels [109]
2 years ago
13

Find BC please help!

Mathematics
1 answer:
Ulleksa [173]2 years ago
3 0

Answer:

BC=23

Step-by-step explanation:

Use sine rule:

x/sinX=y/sinY

BC/sinA=AB/sinC

BC/sin61=9/sin20

BC=26.3142396015*sin61

BC=23.0149525338

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A local citizen wants to fence a rectangular community gardenn. The length of the garden should be at least 110ft,and the distan
Arte-miy333 [17]
The question is incorrect
the correct question is
A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutions

let
x---------------> t<span>he length of the garden
</span>y---------------> the wide of the garden

we know that
x>=110
2x+2y <=380---------------> x+y <= 190

Part A) <span>Write a system of inequality that model the possible dimensions of he garden
</span>
the answer part A) is
x>=110
x+y <= 190


Part B) <span>Graph the system to show all possible solutions

using a graph tool
see the attached figure
the solution is the triangle show in the figure

</span><span>the possible solutions of y (wide) would be between 0 and 80 ft
</span>the possible solutions of x (length) would be between 110 ft and 190 ft

5 0
3 years ago
Given that cos (x) = 1/3, find sin (90 - x)
ddd [48]

Answer:

\sin(90^{\circ} - x)=\frac{1}{3}

Step-by-step explanation:

Given: \cos (x)=\frac{1}{3}

We have to find the value of \sin(90^{\circ} - x)

Since Given \cos (x)=\frac{1}{3}

Using trigonometric identity,

\sin(90^{\circ} - \theta)=\cos\theta

Thus, for  \sin(90^{\circ} - x) comparing , we have,

\theta=x

We get,

\sin(90^{\circ} - x)=\cos x=\frac{1}{3}

Thus, \sin(90^{\circ} - x)=\frac{1}{3}

3 0
3 years ago
Read 2 more answers
A baker made two cakes of the same size. • At the end of the day, there was 23 of a chocolate cake left. • There was 56 of a str
Murrr4er [49]
This is the concept of algebra, To solve the question  we proceed as follows;
Number of chocolate cake left=23 
The number of pieces that was left after the cake was divided into 2 equal pieces will be:
23*2
=46

Number of strawberry cake left = 56
The number of pieces that was left after the cake was divided into 3 equal pieces will be:
56*3
=168

Comparing the two fraction, the flavor that had larger pieces was strawberry cake;
This cake was larger compared to chocolate by:
168-46
=122
The answer is Strawberry by 122 of a cake
5 0
3 years ago
This is timed and Will mark BRAINLIEST!!!
gulaghasi [49]

Answer:

the last one with 2y in the denominator

3 0
2 years ago
The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a par
Mila [183]

Answer:

Part A: Triangles GCB and PBE

Part B: They're similar because they have the same internal angles.

Part C:

250/400 = BE/450

112500/400 = BE

BE = 281.25 ft

250/400 = PE/350

87500/400 = PE

PE = 218.75 ft

5 0
2 years ago
Read 2 more answers
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