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stiks02 [169]
3 years ago
5

Solve the system of equations -7x - 6y = 4 x= -3y + 8

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
7 0
You can use the substitution method for this problem
Since -3y+8=x you can
Use the equation -7(-3y+8) -6y=4
You then distribute and solve
21y-56-6y=4
15y=60
Y=4
You then plug y into one of the original equations
X=-12+8
X=-4
(-4,4)
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To which real number sets does the number 13 belong?
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3 0
3 years ago
We want to place a bench measuring 7.05 feet in the center of a platform that is 40.75 feet long
AnnyKZ [126]
40.75 - 7.05= 33.7
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5 0
3 years ago
Simplify the expression show work<br> -3(4a-5b)
galben [10]

Answer:

- 3(4a - 5b) \\  - 12a - 15b \:  \: answer

Step-by-step explanation:

please mark me brainliest

6 0
3 years ago
AFTER HALLOWEEN, PUMPKINS WERE 25% OFF. AMY BOUGHT 2 BIG PUMPKINS THAT WERE ORIGINALLY $7 EACH. HOW MUCH DID SHE SPEND (BEFORE T
Lady bird [3.3K]

Answer:

$ 10.50

Step-by-step explanation:

we can use a proportion to answer this question

25 : 100 = x : 7

x = (25 * 7)/100 = $1.75 (value of the discount)

Final price = 7 - 1.75 = $5.25

she bought two = 5.25 x 2 = $10.50

3 0
2 years ago
Read 2 more answers
2. Mr. Andrew wants to give each of his students an equal number of the crayons he bought. There are 32 students in Mr. Andrew’s
Vladimir79 [104]

Answer:

Step-by-step explanation:

2.

Because we don't know how many crayons he bought we will call it c.

c = total number of crayons purchased

T = total number of crayons each student gets

To determine how many crayons each student gets we divide c by 32, because that's the number of students in his class.

c / 32 = T

So let's say he purchased 120 crayons.

c = 120

120/32 = T

T = 3.75

Since he can't give a fraction of a crayon, in this case, each student will get 3 crayons.

3.

We will now pretend there are 24 crayons in 1 box.

So T still equals the total number of crayons each student gets and c still equals number of crayons purchased, but now we also have b which equals the number of crayons in 1 box.

c = total number of crayons purchased

T = total number of crayons each student gets

b = number of crayons in 1 box

x = number of boxes purchased

So b*x = c

We can still write the equation:

c / 32 = T

We know T = 12 So we plug 12 in for T

c / 32 = 12  Now multiply each side by 32, so 32 will cancel on the left.

32c/32 = 12 * 32

c = 12 * 32

c = 384

So if he needs to purchase 384 crayons we can use our other equation.

b*x = c    

b = 24

c = 384

So we plug those in.

24x = 384  Divide each side by 24 so 24 will cancel on the left.

24x/24 = 384/24

x = 384/24

x = 16

So he needs to buy 16 boxes of crayons in this instance. We can figure out how many boxes he bought in #2 by using the same equation.

b*x = c  

c = 120 in #2

b =24

24 * x = 120

24x/24 = 120/24

x = 120/24

x = 5

So for each student to have 12 crayons he needs to purchase 11 more boxes (16 - 5 = 11).

This will work for whatever numbers you were given.

Remember:

c = total number of crayons purchased

T = total number of crayons each student gets

b = number of crayons in 1 box

x = number of boxes purchased

b*x = c

c / 32 = T

3 0
3 years ago
Read 2 more answers
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