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Ilia_Sergeevich [38]
3 years ago
14

Oswald told Sarah that 1240×5/6 > 12 for 40 which of the following explains why oswald is correct or incorrect

Mathematics
2 answers:
liubo4ka [24]3 years ago
4 0

Answer:

A, but that isn't really the most mathmatical way to put it, and it might not apply to other equations.

Veronika [31]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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The answer is b hope is the correct one
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PLS HELP :(
faust18 [17]

Answer: 47.1

Step-by-step explanation:

1/3πr^2h

=1/3×π×32×5

=15π

= 47.123889803847 feet3

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There are 4 boxes of cookies each box holds 8 cookies how many childrrn can be served 2 cookies each
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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

3 0
3 years ago
How to solve this problem?
anyanavicka [17]

g = number of goblins

w = number of wizards

There are 220 club members altogether, so

g + w = 220

There are 20% more goblins than wizards, so

g = 1.2 w

Substitute this into the first equation and solve for w, then for g.

1.2 w + w = 2.2 w = 220  ==>  w = 100

g = 1.2 w  ==>  g = 120

8 0
3 years ago
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