We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula
we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3
log3(a/3)=[log (a/3)]/[log (3)]
the answer is
[log (a/3)]/[log (3)]
The answer would be D.
Randall should choose the rebate offer because the shoes will be $2.40 less than if he chooses the sale price.
88 - 20% = 70.4
88 - 20 = 68
70.4 - 68 = 2.4 (2.40)
Please mark me brainliest! Thanks!
Perpendicular bisector theorem
30 apples bc 5x6 (5 six times) =30
Sqrt[x] = -x
x= x ^ 2
x - x^2 = 0
-x(x-1)=0
x(x-1)=0
x = 1 or x = 0
sqrt 1 isn not equal to 0
x= 0
