Answer:
J - Janeta's age M - mother's age
A) (J-5) = .2 * (M-5)
B) J = (1/3) * M
Subtracting 5 from both sides of B:
B) J -5 = (1/3)M -5
then we substitute the right side of this into the left side of A and we get
(1/3)M -5 = .2 M -1
.333333333333M -5 = .2M -1
.1111111111111111111M = 4
Mother's Age = 36
Janeta's Age = 12
Step-by-step explanation:
Answer:
C = -6
Step-by-step explanation:
1 +-7 =-6:::::::::::::::::::
The answer is 9.65x10^14 because in order for the decimal point to be between 9 and 6 you need to move 14 decimal places back
Answer:
57
Step-by-step explanation:
Answer:
<u><em>The Father is currently 47 and the Son is 7</em></u>
Step-by-step explanation:
Let F and S be the present ages of Father and Son, respectively.
We are told that <u>(F-2) = 9(S-2)</u> [2 years ago, father age was nine times the son age]
We also learn that <u>(F+3) = 5(S+3)</u> [3 years later it will be 5 times only]
Take the first expression and isolate one of the variables (S or F). I'll isolate F:
(F-2) = 9(S-2)
F = 9S - 16
Now use this in the second expression:
(F+3) = 5(S+3)
((9S-16)+3) = 5(S+3)
9S-13 = 5S+15
4S = 28
S = 7
Since F = 9S-16,
F = 9*(7)-16
F = 47
<u><em>Father is 47 and Son is 7</em></u>
CHECK:
Was the father 9 times the age of his son 2 years ago?
Father would have been 45 and son 5. Yes, 9*5 = 45
In 3 years will he be 5 times older than his son? Yes, Father would be 50 and son would be 10. 5*(10) = 50
