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amid [387]
3 years ago
13

When 2(3/5x+2 3/4 is simplified what is the resulting expression

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

A. 1 7/10x+2 1/2y+6

B. 7/10x+2 1/2y+6

C. 7/10x+8 1/2y+6

D. 1 7/10x+4 1/4y+3

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Jonathan’s age is one-third Belindas age now in 12 years time Belinda will be M years old
chubhunter [2.5K]

Step-by-step explanation:

quisiera ayudarte pero no hablo inglés :(

4 0
3 years ago
15% of the parking spaces at a school are reserved. The school has 12 reserved spaces. How many parking spaces are there in tota
Strike441 [17]

Answer: 76

Step-by-step explanation:

well, we know that 15% of the X is 12, so we first use 6 15%, which is 90% 6X12=72. next, we would use 12/3, which is 4. 72+4=76.

3 0
2 years ago
Read 2 more answers
How to solve 6/12=2/c
Vlad1618 [11]
All you have to do here is some simplifying. 

6/12 = what
6 divided by 12 = 1/2

1/2 = 2/4

There! We have our missing value

6/12 = 2/4

Answer: c = 4
4 0
3 years ago
Read 2 more answers
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2
drek231 [11]

Answer:   ∠A=48°,∠B=48°,∠C=84°.


Step by-step explanation:

Given:  AD and BE are the angle bisectors  of ∠A and ∠B

i.e ∠6=∠7    ( ∵ Angles formed after  AD bisected ∠A)

∠4=∠5       ( ∵ Angles formed after  BE bisected ∠B)

Also,  DE║AB

⇒ ∠2=∠7   (∵ Alternate interior angles)

   ∠3=∠6   (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x     ..(1)

To Find:  ∠A,∠B,∠C.

Solution:  ∠2=∠7 (∵ Given)    ...(2)

∠2=∠4  (∵ angles on the same segment)    ...(3)

∠4=∠5 =∠B/2 (∵ Given)    ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

6 0
4 years ago
SHOW that (x + 3) and (x - 2) are factors of f(x) = x4 + 10x3 + 23x2 -<br> 34x - 120.
Anna35 [415]
If f(x) = 0 then it is a root

x + 3 = 0
x=-3
f(-3) = (-3)^4 + 10(-3)^3 + 23(-3)^2 - 34(-3) - 120 = 0

x - 2 = 0
x=2
f(2) = (2)^4 + 10(2)^3 + 23(2)^2 - 34(2) - 120 = 0
8 0
2 years ago
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