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3 years ago

Mike travels 13 miles per 2 hours on his bike.

Mathematics

1 answer:

LiRa [457]3 years ago

4 0

Answer:

It took Markus half an hour to drive home from work. He averaged 34 miles per hour. How far does Markus live from his work?

Solution

We are given that it takes 1/2 an hour for the trip. This is a time:

t = 1/2

We are given that he averages 34 miles per hour. This is a rate:

r = 34

We are asked how few he has traveled. This is a distance. We use the d=rt equation:

d = rt

= (34)(1/2)

= 17

Markus lives 17 miles from work.

Now try one by yourself. If you want to see the answer, put your mouse on the yellow rectangle and the answer will appear.

Exercise 1

The current along the beach is moving towards the south at 1.5 miles per hour. If a piece of debris is placed into the water, how far will the current take it in 6 hours?

Step-by-step explanation:

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Help pls!!! I WILL BRAINIEST!!!!

slavikrds [6]

The maximum the company can expect for returned items is $4190.

<h3>What is the percentage?</h3>

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, The average daily profit of an electronics store is $27,235.

The company estimates that 15% is lost each day to returns.

∴ The amount of return is (15/100)×27135.

= 0.15×27125.

= $4068.

Now this has an error of ± 3%, therefore the maximum the company can expect for returned items is {(100 + 3)/100}×100

= 1.03×4068.

= $4190.

Learn more about percentages here :

brainly.com/question/24159063

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4 0

1 year ago

A researcher wants to estimate the impact prenatal care during pregnancy can have on anemia rates in pregnant mothers by conduct

Murrr4er [49]

Answer:

At least 1022 new moms should be recruited.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How many individuals should the researcher recruit to participate in the study if the researcher wants to be 95% confident that the margin of error is no more than 3.0%?

At least n new moms should be recruited.

n is found when $M = 0.03, \pi = 0.397$