Answer:
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Explanation:
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We are given the density of mercury which is equal to 13.6 g/ml. Substances which sink in this metal should have densities higher than the density of the metal, otherwise they would float. The substance thta would sink in mercury is C. gold
Answer:
Manganese (II) Phosphate
Explanation:
Mn3(PO4)2 is the compound given in this question. Manganese is the metal and hence it will come first in the name. Along with the name of metal it is essential to determine the valency of the metals based on the compound structure.
Here 2 PO4 attaches with 3 Mn
Valence of PO4 is -3
So the total electrons contributed by PO4 is 3*2 = 6
Now Mn has 3 atoms in the compound. Thus, per atom the valency must be 2 in order to satisfy -6 charge of PO4
Thus, valency of Mn is 2
So, the name will be
Manganese (II) Phosphate.
True?
Step by step explanation:
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One mole of aluminum oxide or Al₂O₃ is 102 g/mol . It contains 54 g of Al metal. Thus, 25.5 tones of aluminum oxide contains 13.5 tones of Al. Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones.
<h3>What is aluminum?</h3>
Aluminum is 13 the element in periodic table. It is an electropositive element and exhibit metallic properties. Aluminum easily forms its oxides by reacting with atmospheric oxygen.
The molar mass of aluminum oxide Al₂O₃ is 102 g/mol. The atomic mass of Al is 27 g/mol. Thus 102 g of Al₂O₃ contains 54 g of Al. Therefore, the mass of Al in 25.5 tones or 25.5 ×10⁶ g of Al₂O₃ is calculated as follows:
mass of Al = (25.5 ×10⁶ g × 54 g) / 102 g
= 13.5 ×10⁶ g = 13.5 tones.
Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones
To find more on aluminum, refer here:
brainly.com/question/12768349
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