Answer: C4H
Explanation:
An hydrocarbon is a compound with carbon and hydrogen atoms only covalently linked together.
Thus, all hydrocarbons have a basic formula of CH.
Now, mass of hydrocarbon = 100%
Mass of hydrogen = 20%
Mass of carbon = (100% - 20%) = 80%
i.e Carbon : Hydrogen
= 80% : 20%
= (80% / 20%)
= 4 : 1
Thus, the empirical formula of the hydrocarbon is C4H
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Na and Cl,
E.N of Chlorine = 3.16
E.N of Sodium = 0.93
________
E.N Difference 2.23 (Ionic Bond)
For C and O,
E.N of Oxygen = 3.44
E.N of Carbon = 2.55
________
E.N Difference 0.89 (Polar Covalent Bond)
For N and Cl,
E.N of Chlorine = 3.16
E.N of Notrogen = 3.04
________
E.N Difference 0.12 (Non-Polar Covalent Bond)
For B and O,
E.N of Oxygen = 3.44
E.N of Boron = 2.04
________
E.N Difference 1.40 (Polar Covalent Bond)
Answer:
Group 1: LiOH, NaOH, KOH
Group 2: Ca(OH)2, Sr(OH)2, Ba(OH)2
Explanation: