All categories

2 years ago

Determine if the following event is mutually exclusive:

Mathematics

1 answer:

sp2606 [1]2 years ago

6 0

Answer:

Ask yourself: "Can I roll a prime number and an odd number at the same time?"

Since the answer is "yes it is possible" (eg: rolling a 3), this means the two events are not mutually exclusive. Mutually exclusive events have nothing in common.

In terms of a venn diagram, mutually exclusive events have no overlapping shared region.Step-by-step explanation:

You might be interested in

Clare used 25% less butter this month than last month when baking holiday treats. If she used 240 tablespoons of butter last mon

amm1812

Answer:

I think she used 180 tablespoons of butter this month.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The scatter plot below shows the relationship between drop height and speed of a roller coaster.

attashe74 [19]

Answer: I believe it is Response 3

Step-by-step explanation:

3 0

3 years ago

Find the mean of the integers. −54,−32,−70,−25,−65,−42<br><br> pls help

Nataliya [291]

The answer is -42.166

3 0

2 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

6 0

3 years ago

A bicycle manufacturing plant is producing the first few frames for their new electric bicycle design. The first batch of 60 fra

Dmitry_Shevchenko [17]

Answer:

a) 131/450

b) 1233/1276

Step-by-step explanation:

P(bad) = P(1st batch)*P(bad 1st batch ) + P(2nd batch )*P(bad 2nd batch) + P(3rd batch )*P(bad 3rd batch)

p(bad) =(60/360)*(1/3) + (120/360)*(1/4 ) + (180/360)*(1/5)

= 43/180

And that of P(good )

= 1 - 43/180

= 137/180

P(defective) = P(bad)*P(defective /bad) + P(good)*P(defective /good)

= (43/180)*(9/10) + (137/180)*(1/10)

= 131/450

P(Bc I Dc ) = P(good)*P(not defective |good) / P(not defective)

= (137/180)*(1 - 1/10) / (1 - 131/450)

= 1233/1276

5 0

3 years ago