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3 years ago

Which side of the polygon is exactly 6 units long?

Mathematics

1 answer:

stiks02 [169]3 years ago

7 0

Answer:

its CD because you see the points for

Step-by-step explanation:

-6,-8 and 4,-8

hope its right

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What is the area of this figure? Need it now!!

saw5 [17]

Answer:

The area is 452cm

Step-by-step explanation:

For the big square we have to multiply 15*18 and that is the area so-

15*18=270

Next we multiply 13 and 14

13*14=182

And now we add 270 and 182 to get the total area

270+182=452

7 0

3 years ago

Read 2 more answers

How do you work out 3^2+2^3 indices

Bingel [31]

3^2 +2^3

9+2^3

9+8

Answer : 17

4 0

3 years ago

At PRMS, 25% of the 124 students Mrs. Pasternak teaches buy their lunches in the cafeteria. How many students buy their lunches

Ksju [112]

25% = 0.25
124 x 0.25 = 31

31 students bought their lunch.

Part = 31
Percent = 25%
Whole = 124

Hope this helps! ✨

6 0

3 years ago

Select all that show multiplication: A 3/4 B (3)(4) C 3x4 D 3*4 E 3(4)

gregori [183]

B
C
D
E
They all show multiplication

8 0

3 years ago

Read 2 more answers

Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa

Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation

n=580 represent the random sample taken

X represent the seafood sold in the country that is mislabeled or misidentified by the people

$\hat p=0.25$ estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

$\alpha=0.01$ represent the significance level (no given, but is assumed)

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204$

$0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296$

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

Part c

A government spokesperson claimed that the sample size was too small, relative to the billions of pieces of seafood sold each year, to generalize. Is this criticism valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0

4 years ago