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Korolek [52]
3 years ago
5

Help

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

Bro same question for my test

Step-by-step explanation:

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Determine which lines are parallel and which are not parallel. Explain your reasoning.
NeX [460]

Answer:

If M and N are parallel, then the correspondent angles generated by the intersection with line R (or line S) should be equal.

So, if M and N are parallel, we should get that angles 2 and angle 4 are equal, as both of these are on the fourth quadrant of the intersection with the same line.

Similarly, if R and S are parallel, then correspondent angles generated by the intersection with line M (or line N) should be equal, this means that:

angle 3 and angle 7 should be equal.

Also remember that if we have two lines intersecting, generating 4 angles, any pair of two adjacent angles will always add to 180°.

Here we have two cases:

1)  m∠3=69°, m∠7=71°

Here we can see that:

m∠3 ≠ m∠7

Thus, lines  R and S are not parallel.

And here we do not have any information on the angles 1, 2, 5, and 6, so we can't compare the angles generated by line N with the ones generated by line M, so we can not know if lines N and M are parallel or not.

2) Now we have that:

m∠3=76°  , m∠8=114°

Notice that angle 8 and angle 7 are adjacent, then we have that:

∠7 + ∠8 = 180°

And we know that:

∠8 = 114°

Then:

∠7 + 114° = 180°

∠7 = 180° - 114° = 76°

Then we have:

∠7 = ∠3

From this we can conclude that lines R and S are parallel.

(again, we can not do anything with lines N and M)

6 0
2 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
Andre is in charge of cooking broccoli and zucchini for a large group. He has to spen 17 dollars and can carry 10 pounds of vegg
Feliz [49]

Answer:

lol sry I have no idea

Step-by-step explanation:

I have no clue bro

3 0
2 years ago
Find a fraction or mixed number that is between the two numbers -3/4 -1/3
Mandarinka [93]

Hey there!


-3/4 - 1/3

= -3/4 + (-1/3)

≈ -9/12 - 4/12

= -9 - 4 / 12 - 0

≈ -9 - 4 / 12

= -13 / 12

≈ -1 1/12


Therefore, your answer is/

-13/12 or -1 1/12

EITHER OF THOSE SHOULD BE CORRECT BECAUSE THEY ARE EQUIVALENT OR THE SAME THING.


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

6 0
2 years ago
The functions f(x) and g(x) are shown on the graph.
Grace [21]

Answer:

I believe the answer is D.

6 0
3 years ago
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