Answer:

Step-by-step explanation:
We are given the following in the question:
A storage shed is to be built in the shape of a (closed) box with a square base.
Volume = 150 cubic feet
Let s be the edge of square base and h be the height.
Volume of cuboid =

where l is the length, b is the base and h is the height.
Volume of box =

Area of base =

Cost of concrete for the base = $4
Cost of base($) = 
Area of roof =

Cost of material for the roof = $2
Cost of roof ($) = 
Area of 4 walls =

Cost of material for the side = $2.50
Cost of material of side($) =

Total cost
= Cost of base + Cost of 4 sides + Cost of roof

is the required cost function.
Answer:
The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.
Step-by-step explanation:
The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.
When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.
Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:
Purple flowers with round seeds: 9/16
Purple flowers with wrinkled seeds: 3/16
White flowers with round seeds: 3/16
White flowers with wrinkled seeds: 1/16
The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
= 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
= 797 milligrams.
So the flea weighs 797 milligrams more than the ant.