I'm more visual, but if you're not, and this confuses you, ask me, and I'll explain it.
Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
A] A function is a special type of relation for which there is a rule that pairs each input with exactly one output.
Step-by-step explanation:
Answer: the answer is B which is $609.50
Step-by-step explanation:
I mean the equation is already set up all there is to do is solve put it in the calculator and you should get $609.50
