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Sedbober [7]
3 years ago
7

In the triangle below, the sine of xº is 0.6. What is the sine of y

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

The answer is "\sin x=0.6"

Step-by-step explanation:

Please find the attached file of the graph.

Given:

\to \sin x = 0.6\\\\\to x+y+90=180^{\circ} \\\\\to x+y=90^{\circ} \\\\\to y=90-x\\\\  

Let  

\to \cos y= \cos(90-x) =\sin x=0.6

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
MrRa [10]

Answer:

C 0 solutions

Step-by-step explanation:

8x+47 = 8(x+5)

Distribute

8x+47 = 8x+40

Subtract 8x from each side

47 = 40

This is never true so there are no solutions

8 0
4 years ago
Read 2 more answers
What is the answer to the equation 4a+26-9a-17=26?
podryga [215]
First you have to put all of your common numbers together. 4a and 9a go together. You then subtract those because 9 is negative (-9). Then you get -5a. Now move on to your other numbers. You have 26 and 17. 17 is negative as well (-17), so you subtract it from 26. That gives you 9.
Your new equation is -5a + 9 = 26
Now you subtract 9 from both sides. Your positive (+9) will cancel out with your negative (-9). Then subtract it from 26. 9 minus 26 is 17. 
Now your equation is -5a = 17
Since it's negative, you're going to add it (5) to both sides. 
Your 5's cancel out, and 17 + 5 is 22. 
a = 22
22 is the answer 

5 0
4 years ago
What's the probability of pulling two red cards in a row from a deck of cards?​
monitta

Hey there! I'm happy to help!

Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.

If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.

We multiply the probabilities of these two events to find the probability of them both happening.

1/2×25/51=25/102

The probability of picking two red cards in a row is 25/102 or around 24.5%.

Have a wonderful day! :D

8 0
3 years ago
Mel has to put the greatest number of
Dmitry_Shevchenko [17]

Mel should use the least  common multiple to solve the problem

<u>Solution:</u>

Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.  

We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?

He should use least common multiple.

Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.

Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.

So the remaining method to choose is L.C.M.

Hence, he should use L.C.M method.

6 0
3 years ago
On tax free weekend Michael bought 3 shirts that cost $19.50 each. He used a coupon for 25% off of the total purchase. Rounded t
trasher [3.6K]
His total would be 58.50 then you multiply by .25 percent then you take 14.63 and subtract that from the total and you get 43.87
8 0
3 years ago
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