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icang [17]
3 years ago
9

A chocolate company selects 50 random packages to check their weight. It finds that 2 packages have an incorrect weight. How man

y packages out of 2000 should the company predict have an incorrect weight.
Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

80

Step-by-step explanation:

A company selects 50 random packages from which two of them have an incorrect weight. That is to say: 4% of the packages are incorrrect.

Now if the company selects 2000 packages, we could predict that 4% of them could be incorrect. We know that 2000×0.04 = 80.

Therefore, 80 out of 2000 packages are expected to have an incorrect weight.

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6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

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When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

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Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

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n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

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Read more about lines of intersections at:

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Hope this helps!

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