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riadik2000 [5.3K]
3 years ago
5

GUYS HELP ITS A TEST AND IMMA FLUNK 10/9 - 7/6=

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0

Answer:

10/9−7/6= -1/18

Step-by-step explanation:

levacccp [35]3 years ago
3 0

Answer: 18

Step-by-step explanation:

: cross multiply and get 63-60= 3 then multiply the denominators 9 *6 and get 54, 3/54 = 18

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A

Step-by-step explanation:

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3 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

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3 0
3 years ago
Weldon installed a square hot tub in his backyard and wants to enclose it with a fence. The fence will enclose an area that is 4
Katarina [22]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Averigua: Cuantos habitantes tiene tu localidad y cuantos tu provincia Calcula A qué porcentaje de la población del Ecuador con
Diano4ka-milaya [45]

Answer:

La Provincia del Guayas comprime el 25.1% de la población de Ecuador. A su vez, la Ciudad de Guayaquil tiene una población igual al 15.58% de la población ecuatoriana.

Step-by-step explanation:

Dado que vivo en la Provincia del Guayas, y en la ciudad de Guayaquil, los datos de población solicitados son los siguientes:

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17.475.570 = 100

4.387.434 = X

4.387.434 x 100 / 17.475.570 = X

438.743.400 / 17.475.570 = X

25,10 = X

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17.475.570 = 100

2.723.665 = X

2.723.665 x 100 / 17.475.570 = X

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7 0
3 years ago
The number of withdrawals a bank processes in a day follows a random variable X. The number of deposits in a day is represented
Serhud [2]

Answer:

Check the explanation

Step-by-step explanation:

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T+1

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= (r+1)\left ( \frac{p}{1-q} \right )^{r} * \frac{-p}{(1-q)^2} * (-q)

= (r+1)\left ( \frac{p}{p} \right )^{r} * \frac{-p}{(p)^2} * (-q)

= \frac{(r+1)q}{p}

4 0
3 years ago
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