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scZoUnD [109]
3 years ago
10

What is an irrational number between 7.7 and 7.9 explain why it is irrational. And include the decimal approximation of the irra

tional number to the nearest hundredth . HELP PLEASE!!
Mathematics
2 answers:
MissTica3 years ago
5 0
NightowlIt can be proven that between any two real numbers there exists a rational number. Therefore there exists a rational number r such that
<span>7.7+<span>2–√</span><r<7.9+<span>2–√</span></span>By calculator we can find a rational number r that satisfies these condition, I choose 9.2. Now subtract square root 2.<span>7.7<9.2−<span>2–√</span><7.9

</span>so the answer is between 7.7 and 7.9
rational  number : 7.8
<span>irrational number :  9.2 - √2</span>
KonstantinChe [14]3 years ago
5 0
1st- An irrational number is a non terminating decimal and a non repeating decimal also: Examples:
a) 10.5494737891157.... is an irrational number (decimal will continue for ever
b) 15.1231231213123123123.....(Not irrational because decimal are repeating for ever
c) 121.1201200120001200001... (Rational because decimal go foe ever and they are not being repeated.
Now we have to find an irrational number between 7.7 and 7.9 (obviously there are an infinity of such numbers: So

7.7<x<7.9.Take any number between 7.7 and 7.9, say 7.8 and add to its decimal whatever number of digits you may choose. But to be on the safe side I would advise the following (non repeated) number:
7.810 100 1000 10000 10000.....
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6 0
3 years ago
Read 2 more answers
4. Which relation is a function?
postnew [5]

<u>Answer:</u>

The last option choice [(1,3), (2,6), (3,9), (4,12)

<u>Step-by-step explanation:</u>

The key idea to understand in a function/relation is that each input can only have one output. Inputs are your x-variables and outputs are your y-variables.

In the first relation, you see the two points (3,4) and (3,5). 3 is your input [since its x] , however, it gives you two outputs [y's], 4 and 5. So you can cross out the first option.

In the second relation, look at the points (3,4) and (3,3). Again, both have the same input 3, but different outputs, 4 and 3. So you can cross out the second option.

In the third relation, look at all of the points. They all share a common input, 1, but different outputs, 2, 3, 4, and 5. So you can cross out the third option too.

Lastly, look at the last relation. They all have different inputs but the key thing to look at here is that each input only has one corresponding output. Thus, this is the right answer.

I hope this helps!

8 0
3 years ago
I need the one on the right please lol I don’t get it
andrezito [222]

Answer:

Step-by-step explanation:

16- R

17 P

18 A

19 H

20  B

5 0
3 years ago
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I need help on a question
NeX [460]

Jb, this is the solution:

If T = (x + 3, y + 1),

T3 = 3(x + 3, y + 1)

T3 = 3x + 9, 3y + 3

The correct answer is C.

7 0
1 year ago
Subtract and simplify.<br><br> (y2−3y−5)−(−y2−7y+4)<br> *Both Y's with no variable are squared
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=(y2-3y-5)-(-y2-7y+4)
=y2-3y-5+y2+7y-4
=2y2+4y-9

Hope this helps! :)
3 0
3 years ago
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