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Triss [41]
3 years ago
13

When Ms. Sugar turned on her oven, the temperature inside was 70 degrees Fahrenheit. The temperature began to rise at a rate of

20 degrees every minute. How long did it take for the oven to reach 350 degrees Fahrenheit?
Mathematics
2 answers:
Stella [2.4K]3 years ago
7 0
It would take fourteen minutes
mestny [16]3 years ago
5 0
I am pretty sure you would have to divide 350 /  20 to get 17.5.

It takes 17.5 Minutes the get the oven to reach 350 Degrees F
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Murrr4er [49]

Answer:

x=3

Step-by-step explanation:

6 0
2 years ago
What is the solution to the equation 1 over the square root of 8 = 4(m + 3)?
AnnyKZ [126]
The solution would be ... m = <span>√2 - 48 over 16. Have a good day :)</span>
3 0
3 years ago
Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
Pls need due in 10 minutes
denpristay [2]

Answer:

392.00

Step-by-step explanation:

I'm pretty sure you just multiply the 46m x 2 and 150 x 2 both = the length of the whole track. and then add the two together

3 0
2 years ago
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Elis [28]
There's nothing here to 'match' it with.

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f(z^2) = (z^2)^2 - 3z^2 + 3

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<em><u>g(x)</u></em> is only there to confuse you.
Apparently it was successful.
3 0
3 years ago
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