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dem82 [27]
2 years ago
8

Which of the following functions best describes this graph?

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0
Uuguhpukgifpfdkkddlldoddoododdozo
You might be interested in
Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

  • v_{f} is the final speed
  • v_{i} is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

∴ His acceleration is \frac{1}{15} meters per seconds²

3 0
3 years ago
How many centimeters are in 15 yards?
Ann [662]

Answer:

1371.6 (cm) are in 15 yards

Step-by-step explanation:

1371.6 centimeters are in 15 yards since 1 yard is equal to 91.44.

8 0
2 years ago
Read 2 more answers
This 1 seems really complicated
Fofino [41]
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
________________________________________________________
Given: 
________________________________________________________
 y = - 4x + 16 ; 

 4y − x + 4 = 0 ;
________________________________________________________
"Solve the system using substitution" .
________________________________________________________
First, let us simplify the second equation given, to get rid of the "0" ; 

→  4y − x + 4 = 0 ; 

Subtract "4" from each side of the equation ; 

→  4y − x + 4 − 4 = 0 − 4 ;

→  4y − x = -4 ;
________________________________________________________
So, we can now rewrite the two (2) equations in the given system:
________________________________________________________
   
y = - 4x + 16 ;   ===> Refer to this as "Equation 1" ; 

4y − x =  -4 ;     ===> Refer to this as "Equation 2" ; 
________________________________________________________
Solve for "x" and "y" ;  using "substitution" :
________________________________________________________
We are given, as "Equation 1" ;

→  " y = - 4x + 16 " ;
_______________________________________________________
→  Plug in this value for [all of] the value[s] for "y" into {"Equation 2"} ;

       to solve for "x" ;   as follows:
_______________________________________________________
Note:  "Equation 2" :

     →  " 4y − x =  - 4 " ; 
_________________________________________________
Substitute the value for "y" {i.e., the value provided for "y";  in "Equation 1}" ;
for into the this [rewritten version of] "Equation 2" ;
→ and "rewrite the equation" ;

→   as follows:  
_________________________________________________

→   " 4 (-4x + 16) − x = -4 " ;
_________________________________________________
Note the "distributive property" of multiplication :
_________________________________________________

   a(b + c)  = ab + ac ;   AND: 

   a(b − c) = ab <span>− ac .
_________________________________________________
As such:

We have:  
</span>
→   " 4 (-4x + 16) − x = - 4 " ;
_________________________________________________
AND:

→    "4 (-4x + 16) "  =  (4* -4x) + (4 *16)  =  " -16x + 64 " ;
_________________________________________________
Now, we can write the entire equation:

→  " -16x + 64 − x = - 4 " ; 

Note:  " - 16x − x =  -16x − 1x = -17x " ; 

→  " -17x + 64 = - 4 " ;   Solve for "x" ; 

Subtract "64" from EACH SIDE of the equation:

→  " -17x + 64 − 64 = - 4 − 64 " ;   

to get:  

→  " -17x = -68 " ;

Divide EACH side of the equation by "-17" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  -17x / -17 = -68/ -17 ; 

to get:  

→  x = 4  ;
______________________________________
Now, Plug this value for "x" ; into "{Equation 1"} ; 

which is:  " y = -4x + 16" ; to solve for "y".
______________________________________

→  y = -4(4) + 16 ; 

        = -16 + 16 ; 

→ y = 0 .
_________________________________________________________
The solution to this system set is:  "x = 4" , "y = 0" ;  or write as:  [4, 0] .
_________________________________________________________
Now, let us check our answers—as directed in this very question itself ; 
_________________________________________________________
→  Given the TWO (2) originally given equations in the system of equation; as they were originally rewitten; 

→  Let us check;  

→  For EACH of these 2 (TWO) equations;  do these two equations hold true {i.e. do EACH SIDE of these equations have equal values on each side} ; when we "plug in" our obtained values of "4" (for "x") ; and "0" for "y" ??? ; 

→ Consider the first equation given in our problem, as originally written in the system of equations:

→  " y = - 4x + 16 " ;    

→ Substitute:  "4" for "x" and "0" for "y" ;  When done, are both sides equal?

→  "0 = ?  -4(4) + 16 " ?? ;   →  "0 = ? -16 + 16 ?? " ;  →  Yes!  ;

 {Actually, that is how we obtained our value for "y" initially.}.

→ Now, let us check the other equation given—as originally written in this very question:

→  " 4y − x + 4 = ?? 0 ??? " ;

→ Let us "plug in" our obtained values into the equation;

 {that is:  "4" for the "x-value" ; & "0" for the "y-value" ;  

→  to see if the "other side of the equation" {i.e., the "right-hand side"} holds true {i.e., in the case of this very equation—is equal to "0".}.

→    " 4(0)  −  4 + 4 = ? 0 ?? " ;

      →  " 0  −  4  + 4 = ? 0 ?? " ;

      →  " - 4  + 4 = ? 0 ?? " ;  Yes!
_____________________________________________________
→  As such, from "checking [our] answer (obtained values)" , we can be reasonably certain that our answer [obtained values] :
_____________________________________________________
→   "x = 4" and "y = 0" ;  or; write as:  [0, 4]  ;  are correct.
_____________________________________________________
Hope this lenghty explanation is of help!  Best wishes!
_____________________________________________________
7 0
3 years ago
After going through this module, you are expected to:
Svetach [21]

Answer:

See below

Step-by-step explanation:

<u>Number of squares:</u>

  • 1x1 squares = 8*8
  • 2x2 squares  = 7*7
  • 3x3 squares  = 6*6
  • 4x4 squares  = 5*5
  • 5x5 squares  = 4*4
  • 6x6 squares  = 3*3
  • 7x7 squares  = 2*2
  • 8x8 square  = 1

<u>Total number:</u>

  • 8² + 7² + 6² + 5² + 4² + 3² + 2² + 1 =
  • 64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 =
  • 204
7 0
3 years ago
Read 2 more answers
ASAP NOW JUST ANSWER NO WORK
Naily [24]

Answer:

b.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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