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MaRussiya [10]
3 years ago
12

At what frequency would an inductor of inductance 0.8H have a reactance of 12000^?​

Physics
1 answer:
zheka24 [161]3 years ago
3 0

Explanation:

The inductive reactance X_L is given by

X_L = \omega L = 2 \pi fL

Solving for f, we get

f = \dfrac{X_L}{2 \pi L} = \dfrac{12000\:\text{ ohms}}{2\pi (0.8\:H)}

\:\:\:\:\:\:\:= 2387.3\:\text{Hz}

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