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Hitman42 [59]
2 years ago
8

Your window thermometer shows that the temperature outdoors is 89.3°f. how should you report this temperature to your friend in

israel (i.e., on the celsius scale) and to your si-enthusiastic physicist neighbor (i.e., on the kelvin scale)?
Physics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0
A) Conversion from Fahrenheit to Celsius:
The relationship between the two scales is the following
T_f =  \frac{9}{5}T_c + 32
where
T_f is the temperature in Fahrenheit
T_c is the temperature in Celsius

Re-arranging the formula, we find the inverse relationship:
T_c= \frac{5}{9}(T_f-32)
and we can use this equation to convert T_f = 89.3^{\circ}F into Celsius:
T_c =  \frac{5}{9}(89.3-32)=31.7^{\circ} C

(b) Conversion to Kelvin scale:
The conversion between Celsius scale and Kelvin scale is easier:
T_k = T_c + 273.1
where T_k is the temperature in Kelvin. Using T_c = 31.7^{\circ} C, we find
T_k = 31.7 + 273.1 = 304.8 K
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A metallic conductor has a resistivity of 35 × 10 −6 Ω⋅m. What is the resistance of a piece that is 20 m long and has a uniform
Nitella [24]

Answer:

Therefore the resistance of the conductor is 175Ω

Explanation:

Resistance:

  • Resistance of a metallic conductor is directly proportional to its length(l).
  • Resistance of a metallic conductor is inversely proportional to its cross section area(A).

The notation sign of resistance is R.

The unit of resistance is ohm (Ω).

Therefore,

R \propto l

and

R \propto \frac{1}{A}

\therefore R\propto \frac{l}{A}

\Rightarrow R=\rho \frac{l}{A}

ρ is the proportional constant.

It is also known as resistivity of that metal.

Given ρ=35×10⁻⁶Ω-m

l= 20 m

A= 4.0×10⁻⁶m²

\therefore R=35\times 10^{-6}\times \frac{20}{4.0\times 10^{-6}}

       =175Ω

Therefore the resistance of the conductor is 175Ω

3 0
2 years ago
PHYSICS HELP PLEASE!! MUST SHOW MATH WORK!!
SVETLANKA909090 [29]

<u>Answer:</u>

1) Distance traveled by bird = 403 meter

2)Average speed = 1.66 km /hour

3) Zcceleration = 2 m/s^2

<u>Explanation:</u>

1)  Distance traveled = Speed * Time taken = 31 * 13 = 403 meter.

2)  Average speed = Total distance covered / Time taken for that distance to cover.

    Total distance covered = 2+0.5+2.5 = 5 km

    Time taken = 3 hours

     Average speed = 5/3 = 1.66 km /hour

3)    Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.

  Change in velocity = 14 - 6 = 8 m/s

   Time = 4 seconds

   So acceleration = 8 / 4 = 2 m/s^2

6 0
3 years ago
The Sun has more gravity than the other planets in our solar system because the Sun is
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B the mass of the solar object determines whether the gravity of the object unless the solar object has Sonic property's such as a neutron star which can be the size of Pluto but have the mass of 900 solar masses
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Beta particles are smaller
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The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
2 years ago
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