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Hitman42 [59]
3 years ago
8

Your window thermometer shows that the temperature outdoors is 89.3°f. how should you report this temperature to your friend in

israel (i.e., on the celsius scale) and to your si-enthusiastic physicist neighbor (i.e., on the kelvin scale)?
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0
A) Conversion from Fahrenheit to Celsius:
The relationship between the two scales is the following
T_f =  \frac{9}{5}T_c + 32
where
T_f is the temperature in Fahrenheit
T_c is the temperature in Celsius

Re-arranging the formula, we find the inverse relationship:
T_c= \frac{5}{9}(T_f-32)
and we can use this equation to convert T_f = 89.3^{\circ}F into Celsius:
T_c =  \frac{5}{9}(89.3-32)=31.7^{\circ} C

(b) Conversion to Kelvin scale:
The conversion between Celsius scale and Kelvin scale is easier:
T_k = T_c + 273.1
where T_k is the temperature in Kelvin. Using T_c = 31.7^{\circ} C, we find
T_k = 31.7 + 273.1 = 304.8 K
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iris [78.8K]
Resolution in this sentence refers to a solution to the problem 
5 0
3 years ago
A 1.94-m-diameter lead sphere has a mass of 5681 kg. A dust particle rests on the surface. What is the ratio of the gravitationa
scoundrel [369]

To develop this problem we will apply Newton's laws regarding gravitational forces, both in space and on earth. From finding this relationship, leaving the variable of the dust mass open, we will find the relationship of the forces between the two surfaces. Our values are,

\text{Diameter of the lead sphere} =  D=1.940m

\text{Mass of the lead sphere} =  m_1 = 5681kg

\text{Mass of the dust particle} = m_2

Distance between the center of lead sphere to dust particle

r = \frac{D}{2}

r = \frac{1.940m}{2}

r = 0.97m

Gravitational force of the sphere on the dust particle:

F = \frac{Gm_1m_2}{r^2}

F = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5681kg)(m_2)}{(0.97m)^2}

F = (4.027*10^{-7} N/kg)m_2

Weight of the dust particle

W = m_2 g

W = m_2 (9.8m/s^2)

Ratio of F and W:

\frac{F}{W} = \frac{(4.07*10^{-7}N/kg) m_2)}{m_2(9.8m/s^2)}

\frac{F}{W} = 4.153*10^{-8}

Therefore the ratio is 4.153*10^{-8}

3 0
3 years ago
En la etiqueta de un bote de fabada de 350 g, leemos que su aporte energético es de 1630 kj por cada 100 g de producto a) La can
fredd [130]

Answer:

(a) 153.37 g

(b) 5705 kJ

Explanation:

(a) To find the amount of bean needed by a man you first calculate the equivalence in beans to 2500kJ

2500kJ*\frac{100g}{1630kJ}=153.37\ g

Thus, 153.37 g has the energy needed by a man that needs 200kJ per day.

(b) The amount of energy per pot of bean is given by:

E=350g*\frac{1630kJ}{100g}\\\\E=5705\ kJ

Thus, the energy is 5705kJ

6 0
3 years ago
What happens when infrared hits a shiny surface
saw5 [17]
Will reflect ........
3 0
4 years ago
(this is somehow part of my science unit, dont ask why)
nirvana33 [79]

Answer:

 Height of coffee mug = 5 cm

Explanation:

  Changing all the data given in to unit cm

              50 mm = 5 cm

              20 cm  = 20 cm

              8 m    = 800 cm

              0.1 km = 100 m = 10000 cm

Since we need to find the height of coffee mug, it's height will not be more than 10 cm.

  So 5 cm is the correct choice.

6 0
4 years ago
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