Answer:
The steps are made to overcome the negative effect of friction or to increase the friction in the mud.
Explanation:
The following step can be taken when the 4 wheels of our 4 wheeler stuck in the mud are:
(a) First put some sand or rock near the tires to increase the friction to overcome the slipping of tires.
(b) Try to reverse the car and stop and will try to accelerate in the forward direction.
(c) Use the rope, by which one end can be tie to the tree another to the car and then accelerate.
(d) Put some wooden blocks in between the tires which can help.
Answer:
615.15 K/m
33 K
Explanation:
A = 0.897 m^2, Heat per second = 27700 W, ΔT/Δx = ?, Δx = 0.0537 m
K = 50.2 W/mK
heat per second = K x A x ΔT/Δx
27700 = 50.2 x 0.897 x ΔT/Δx
ΔT/Δx = 615.15 K/m
Now ΔT = ΔT/Δx x Δx
ΔT = 615.15 x 0.0537 = 33 K
In physical chemistry, the terms body-centered cubic (BCC) and face-centered cubic (FCC) refer to the cubic crystal system of a solid. Each solid is made up simple building blocks called lattice units. There are different layouts of a lattice unit.
It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.