coulomb's law
f repulsive = q1q2/4 pi epsilon nought r squared
0.1= q1q2/4 pi epsilon nought 0.911 squared
q1+q2= 7.50 µC
0.1= q1(7.5µC-q1)/4 pi epsilon nought 0.911 squared
solve for q1
Answer:
0.1 N
Explanation:
using F = ma yields 0.1 N.
net
Answer:
oh for real?
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
Answer:
<u>20 Minutes</u>
<u></u>
Explanation:
Well we know Mph (Miles per hour) is distance over time : 
R (rate) = 60
d (distance) = 20
t (time) = Unknown
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
R =
↓
60 =
↓
t = 
↓
t =
or 0.3333
<em>So basically it would take one third of an hour. Lets change these units to minutes.</em>
60 * 0.333333 = 20
<em>So it would take you </em><u><em>20 minutes</em></u><em> to drive 20 miles on a bus that drives 60 mph</em>
<em />
Hope that helps
<em>~Siascon~</em>