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Dennis_Churaev [7]
3 years ago
5

Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through

?
index of reflection


index of refraction


angle of incidence


angle of reflection
Physics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

Index of refraction

Explanation:

or refractive index

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Photosynthesis transforms molecules of water and carbon dioxide into Molecules of?
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Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
6CO_2+6H_2O \rightarrow C_6H_{12}O_6+6O_2
and the energy of the light coming from the sun is also used to make the reaction possible.
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When you observe a distant galaxy whose photons have traveled for 10 billion years before reaching earth we are seeing that gal?
expeople1 [14]
In reality we don't see the galaxy we see it's reflection .. the light hits or got emitted by the star travel all the way long to hit our eyes .. we see their reflection . everything around you that you see is it's reflection
8 0
4 years ago
Mars has a mass of about 6.24 Ã 1023 kg, and its moon phobos has a mass of about 9.2 Ã 1015 kg. if the magnitude of the gravitat
Effectus [21]
Given: Mass of Mars Mm = 6.24 x 10²³ Kg;  

           Mass of Phobos Mp = 9.2 x 10¹⁵ Kg

           Gravitational  Force F = 4.47 X 10¹⁵ N

           Gravitational constant G = 6.67 X 10⁻¹¹ N m²/Kg²

           Radius r = ?

Formula: F = GMmMp/r²  derive r

               r = √GMmMp/F

     r = √(6.67 x 10⁻¹¹ N m²/Kg²)(6.24 x 10²³ Kg)(9.2 x 10¹⁵ Kg)/4.47 x 10¹⁵ N

     r = √(6.67 x 10⁻¹¹ N m²/Kg²)5.74 x 10³⁹ Kg²/4.47 x 10¹⁵ N

     r = √8.57 x 10¹³ m

     r = 9,257,429 m

or r = 9.26 x 10⁶ m

8 0
4 years ago
what is the energy (in eV units) carried by one photon violet light that has a wavelength of 4.5e-7?
DaniilM [7]
The energy of a photon is given by
E=hf
where h is the Planck constant and f is the photon frequency.

We can find the photon's frequency by using the following relationship:
f= \frac{c}{\lambda}
where c is the speed of light and \lambda is the photon's wavelength. By plugging numbers into the equation, we find
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.67 \cdot 10^{14}Hz

And so now we can find the photon energy
E=hf=(6.6 \cdot 10^{-34} Js)(6.67 \cdot 10^{14}Hz )=4.4 \cdot 10^{-19} J

We know that 1 Joule corresponds to
1 J = 1.6 \cdot 10^{-19} eV
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E= \frac{4.4 \cdot 10^{-19} J }{1.6 \cdot 10^{-19} J/eV}=2.75 eV
4 0
4 years ago
Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.
Tresset [83]

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

6 0
3 years ago
Read 2 more answers
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