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2 years ago

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Which place value first determines which of the numbers 6.399 or 6.400 is the larger number?

1 answer:

kupik [55]2 years ago

8 0

Comparing the numbers, it is found that the tenths value first determines which of the numbers 6.399 or 6.400 is the larger number.

The decimal numbers are 6.399 and 6.400.

The ones value for each is 6.

For the first value, the tenths digit is of 3, while for the second is of 4.

The tenths digit is the <u>first in which there is a difference</u>, hence, it determines which of the numbers 6.399 or 6.400 is the larger number.

A similar problem is given at brainly.com/question/17248958

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Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

<u>Part A)</u> $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

<u>the answer Part A is</u>

$9-----> A$

<u>Part R)</u> $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

<u>the answer Part R is</u>

$14-----> R$

<u>Part Y)</u> $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

<u>the answer Part Y is</u>

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

<u>the answer Part S is</u>

$23-----> S$

<u>Part O)</u> $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

<u>the answer Part O is</u>

$17-----> O$

<u>Part E)</u> $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

<u>the answer Part E is</u>

$3-----> E$

<u>Part I)</u> $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

<u>the answer Part I is</u>

$20-----> I$

<u>Part D)</u> $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

<u>the answer Part D is</u>

$10-----> D$

<u>Part W)</u> $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

<u>the answer Part W is</u>

$18-----> W$

<u>Part E)</u> $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

<u>the answer Part E is</u>

$7-----> E$

<u>Part T)</u> $0.5(4a+10)=2a+$

Using the distributive property

<u>Part T)</u> $0.5(4a+10)=2a+5$

therefore

<u>the answer Part T is</u>

$1-----> T$

<u>Part R)</u> $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

<u>the answer Part R is</u>

$6-----> R$

<u>Part O)</u> $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

<u>the answer Part O is</u>

$13-----> O$

<u>Part T)</u> $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

<u>the answer Part T is</u>

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

<u>the answer Part W is</u>

$16-----> W$

<u>Part H)</u> $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

<u>the answer Part H is</u>

$2-----> H$

<u>Part E)</u> $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

<u>the answer Part E is</u>

$11-----> E$

Part A) $bu+uv=\ (b+v)$

$bu+uv=u(b+v)$

therefore

<u>the answer Part A is</u>

$5-----> A$

<u>Part F)</u> $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

<u>the answer Part F is</u>

$12-----> F$

<u>Part M)</u> $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

<u>the answer Part M is</u>

$8-----> M$

<u>Part S)</u> $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

<u>the answer Part S is</u>

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

<u>the answer Part T is</u>

$15-----> T$

<u>Part R)</u> $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

<u>the answer Part R is</u>

$19-----> R$

<u>the answer is</u>

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