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igor_vitrenko [27]
3 years ago
9

HELP ME! THE LENGTH OF THE RECTANGLE.

Mathematics
1 answer:
dsp733 years ago
3 0
In order to do this, all you have to do is divide the area by the width
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What is the next numbere 11 13 16 21 28 39​
lubasha [3.4K]
The awnser is 52 because it’s going up by prime numbers
4 0
3 years ago
Kevin opens a savings account with $350. He saves $125 each month. 
Andrej [43]

Answer:

y=350x+125

Step-by-step explanation:

y=350x+125

6 0
3 years ago
Read 2 more answers
Plz help!
OLga [1]

Answer:

a) 3x²-4x-15

b) binomial

5 0
3 years ago
I need help with this work
Anton [14]

Answer:

Please find the answer in the image attached

Step-by-step explanation:

Here we are asked to solve a pair of linear inequalities.

In order to do so , we are first required to plot the two lines with inequalities taking into considerations.

Hence let us plot

x+2y=-4 and 5x+2y=4

let us first plot x+2y=-4

y=\frac{-4-x}{2}

let us plot a table for the same for two random values of x and putting them into above equation

x     y

0    -2

2    -3

Let us now plot these points and join the line .

Let us check whether (0,0) satisfies the in equation or not

0+2(0)≤-4

0≤-4

Which is not true , Hence we shade the portion divided by our line which does not contain (0,0)

Now let us plot the second line 5x+2y=4

y = \frac{4-5x}{2}

let us plot a table for the same for two random values of x and putting them into above equation

x     y

0     2

1     -0.5

Let us now plot these points and join the line .

Let us check whether (0,0) satisfies the in equation or not

5(0)+2(0)≤4

0≤4

Which is true , Hence we shade the portion divided by our line which does  contain (0,0)

Please refer to the image attached with this answer.

now the commonly shaded area as shown in the image will be our solution to the above pair of in equations.

3 0
3 years ago
PLEASE ANSWER QUICKLY
Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

x^3-3x^2+2=x^2-6x+11

Subtract two from both sides

x^3-3x^2=x^2-6x+9
Factor out x^2 from the left side

x^2(x-3)=x^2-6x+9

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

x^2(x-3) = (x-3)(x-3)

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0
2 years ago
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