Question

Divide f(x) by d(x), and write a summary statement in the form indicated.

Answer 1

Answer:

The correct option is B)  $f(x) =(x^2+1)(x^2+4x+5)$

Step-by-step explanation:

Consider the provided function.

$f(x) = x^4 + 4x^3 + 6x^2 + 4x + 5$ and $d(x) = x^2+1$

We need to divide f(x) by d(x)

As we know: Dividend = Divisor × Quotient + Remainder

In the above function f(x) is dividend and divisor is d(x)

Divide the leading term of the dividend by the leading term of the divisor:$\frac{x^4}{x^2}=x^2$

Write the calculated result in upper part of the table.

Multiply it by the divisor: $x^2(x^2+1)=x^4+x^2$

Now Subtract the dividend from the obtained result:

$(x^4 + 4x^3 + 6x^2 + 4x + 5)-(x^4-x^2)=4x^3+5x^2+4x+5$

Again divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{4x^3}{x^2}=4x$

Write the calculated result in upper part of the table.

Multiply it by the divisor: $4x(x^2+1)=4x^3+4x$

Subtract the dividend:

$(4x^3+5x^2+4x+5)-(4x^3+4x)=5x^2+5$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{5x^2}{x^2}=5$

Multiply it by the divisor: $5(x^2+1)=5x^2+5$

Subtract the dividend:

$(5x^2+5)-(5x^2+5)=0$

Therefore,

Dividend = $x^4 + 4x^3 + 6x^2 + 4x + 5$

Divisor = $x^2+1$

Quotient = $x^2+4x+5$

Remainder = 0

Dividend = Divisor × Quotient + Remainder

$f(x) = (x^2+1)(x^2+4x+5)$

Hence, the correct option is B)  $f(x) =(x^2+1)(x^2+4x+5)$