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bija089 [108]
3 years ago
10

A baby blue whale weighed 5520 pounds at birth. After two days, the baby weighed 5710. After 14 days, the baby weighed 8180 poun

ds. Is there a constant of proportionality?
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

Constant of proportionality is 190.

Step-by-step explanation:

To find proportionality constant we will find difference of weights after 2 days and at birth.

5710-5520=190

Now we will find difference of weights after 14 days and at birth. We will divide the difference by 14.

\frac{8180-5520}{14}

\frac{2660}{14}=190

We can see that weights are increasing at a constant rate of 190 pounds per day. Therefore, our constant of proportionality is 190.

solong [7]3 years ago
7 0

Answer:

The constant of proportionality is 190.

Step-by-step explanation:

A baby blue whale weighed 5520 pounds at birth.

After two days, the baby weighed 5710.

Means the weight gain is : 5710-5520=190 pounds

After 14 days, the baby weighed 8180 pounds.

Weight gain = 8180-5520=2660 pounds

So, per day gain = \frac{2660}{14}= 190 pounds

Hence, the constant of proportionality is 190.

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Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

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We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

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3 years ago
if A is the number of degrees and B is the number of grades of any angle ,prove that : B=A+A/9 [FULL PROCESS REQUIRED]​
Gre4nikov [31]
We know
90
∘
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right angle
=
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So
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A
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Hence by the given condition
B
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(
100
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)
=
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9
A
=
A
+
(
A
9
)
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