Answer: Define the problem
Explanation: I just took the test
Answer:
From the question, we have two variables
1. userNum1
2. userNum2
And we are to print "userNum1 is negative" if userNum1 is less than 0.
Then Assign userNum2 with 2 if userNum2 is greater than 10.
Otherwise, print "userNum2 is less or equal 10.".
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare variables
int userNum1, userNum2;
// Accept input for these variables
cin>>userNum1, userNum2;
// Condition 1
if(userNum1 < 0)
{
cout<<"userNum1 is negative"<<'\n';
}
// Condition 2
if(userNum2 > 10)
{
userNum2 = 2;
}
// If condition is less than 10
else
{
cout<<"userNum2 is less or equal to 10"<<\n;
}
return 0;
}
// End of Program.
Answer:
CARBON
Explanation:
HOPE THIS HELPS SORRY FOR CAPS
Answer:
Explanation:
Given that:
The Inside pressure (p) = 1402 kPa
= 1.402 × 10³ Pa
Force (F) = 13 kN
= 13 × 10³ N
Thickness (t) = 18 mm
= 18 × 10⁻³ m
Radius (r) = 306 mm
= 306 × 10⁻³ m
Suppose we choose the tensile stress to be (+ve) and the compressive stress to be (-ve)
Then;
the state of the plane stress can be expressed as follows:
Since d = 2r
Then:
When we take a look at the surface of the circular cylinder parabolic variation, the shear stress is zero.
Thus;
Answer:
331809.5gallon/hr or 92.16gallon/s
Explanation:
What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C
convert 9.4 acre to inches we have=5.896*10^7
How to calculate Peak runoff discharge
1. take the dimension of the roof
2. multiply the dimension by the n umber of inches of rainfall
3. Divide by 231 to get gallon equivalence (because 1 gallon = 231 cubic inches)
5.896*10^7*1.3
7.66*10^7 cubic inches/hr
1 gallon=231 cubic inches
7.66*10^7 cubic inches=331809.5gallon/hr or 92.16gallon/s
this is gotten by converting 1 hr to seconds
331809.5gallon/hr /3600s=92.16gallon/s
