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Nataliya [291]
3 years ago
11

How does sea navigation work?

Engineering
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

a clock

Explanation:

you use a clock in water

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What are the basic types of heat exchangers?
liraira [26]

Answer:

The two large divisions of heat exchangers are direct contact between fluids and indirect contact between fluids.

Explanation:

A heat exchanger is one of the most used equipment at the level of thermal installations, both at the building, tertiary and industrial levels. A heat exchanger is a device designed to transfer heat between two fluids. These two fluids (liquids, gases) can be in contact or separated by a solid barrier. Its use is basic in all types of air conditioning or refrigeration, air conditioning, energy transfer or chemical processes. Heat transmission occurs through convection and conduction.

Classifying heat exchange systems can be carried out using many different criteria. When classifying different types of heat exchangers, different criteria can be taken into account. Taking into account the degree of contact between the fluids, they are grouped into two different types:

Direct Contact Heat Exchanger:

In direct contact exchangers, heat transfer occurs through a physical mixture of the fluids involved in the process. An example of this type of exchangers are the cooling towers. In this case, direct contact occurs between a stream of hot water (fluid to be cooled) using dry and colder air.

Indirect Contact Heat Exchanger :

In a direct type exchanger there is no direct contact between the fluids and they never mix. The fluids are separated by a solid barrier and may also not coincide at the same time.

Indirect contact heat exchangers can be of various types, being the most used, according to their constructive typology:

  • Concentric tubes or double tube .
  • Shell and tubes .
  • Of plates .
  • Compact heat exchangers .
  • Regenerators .

The concentric tube equipments are the simplest that exist since they are composed of two concentric tubes of different diameter so that one of the fluids circulates inside the smaller one and the other does it through the annular space between both tubes.

Shell and tube exchangers are widely used at an industrial level and use a housing with a multitude of tubes inside.

The equipment of plates are formed by a succession of sheets of metal, armed in a frame and separated by joints, which are fixed with a steel shell. The fluid circulates between these sheets.

5 0
4 years ago
Can i join three 12 volts batteriesto give me 24 volts output​
bulgar [2K]

Answer:

YES

Explanation:

If we connect batteries in series then the output voltage is the sum of the individual voltage of each battery i.e if you connect three 12 volts batteries in series then their output voltage will be 12+12+12=36 volts, but the current rating of the batteries in series will be same of the individual battery rating in 'mah'.

But when we connect the batteries in parallel their voltage is not added  but their current rating in mah is addition of their individual rating.

So, If you want 24 volts from three 12 volts battery then you can connect two of them in series and the other one in parallel with them this will give 24 volts and the current will be addition of the two series batteries and the third which is in parallel with them. You can use this configuration if current value is not a big factor.

8 0
4 years ago
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

6 0
4 years ago
A section of highway has a free-flow speed of 55 mph and a capacity of 3300 veh/hr. In a given hour, 2100 vehicles were counted
alexira [117]

Answer:

Space mean speed = 44 mi/h

Explanation:

Using Greenshield's linear model

q = Uf ( D - D^{2}/Dj )

qcap = capacity flow that gives Dcap

Dcap = Dj/2

qcap = Uf. Dj/4

Where

U = space mean speed

Uf =  free flow speed

D = density

Dj = jam density

now,

Dj = 4 × 3300/55

    = 240v/h

q = Dj ( U - U^{2}/Uf)

2100 = 240 ( U - U^{2}/55)

Solve for U

U = 44m/h

5 0
3 years ago
Brainiest and 35 points for the RIGHT ANSWER
Mumz [18]
A level it’s the only one that makes sense
5 0
3 years ago
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