All categories

3 years ago

Why does teachers grade things that are not due yet

Engineering

2 answers:

pav-90 [236]3 years ago

4 0

I think because if you’ve already turned it in they might as well grade asap instead of waiting

White raven [17]3 years ago

4 0

I’m here for the points

You might be interested in

How did dodge become a company

Sonja [21]

Horace and John Dodge founded the Dodge Brothers Company in Detroit in 1900, and quickly found work manufacturing precision engine and chassis components for the city's growing number of automobile firms. Chief among these customers were the established Olds Motor Vehicle Company and the new Ford Motor Company.

6 0

3 years ago

What is the standard half-cell potential for the oxidation of methane under acidic conditions? The reaction for methane is as fo

Yuri [45]

Answer:

The element that is oxidized is carbon.

Its oxidation state increased. It increased from -4 to +4

Explanation:

Oxidation is a process that involves increase in oxidation number.

The oxidation number of carbon in CH4 is -4

C + (1×4) = 0

C + 4 = 0

C = 0 - 4 = -4

The oxidation number of carbon in CO2 is +4

C + (2×-2) = 0

C - 4 = 0

C = 0+4 = 4

Increase in the oxidation number of carbon from -4 to +4 means carbon is oxidized

4 0

3 years ago

Suppose a consumer advocacy group would like to conduct a survey to find the proportion p of consumers who bought the newest gen

Anvisha [2.4K]

Answer:

a) Sample size = 1691

b) 95% Confidence Interval = (0.3696, 0.4304)

Explanation:

(a) How large a sample n should they take to estimate p with 2% margin of error and 90% confidence?

The margin of error is given by

$MoE = z \cdot \frac{\sqrt{p(1-p)} }{\sqrt{n} } \\\\$

Where z is the corresponding z-score for 90% confidence level

z = 1.645 (from z-table)

for p = 0.50 and 2% margin of error, the required sample size would be

$n = \frac{1.645^{2} \cdot 0.50(1-0.50)}{0.02^{2}} \\\\n = \frac{0.6765}{0.0004} \\\\n = 1691\\$

(b) The advocacy group took a random sample of 1000 consumers who recently purchased this mobile phone and found that 400 were happy with their purchase. Find a 95% confidence interval for p.

The sample proportion is

p = 400/1000

p = 0.40

z = 1.96 (from z-table)

n = 1000

The confidence interval is given by

$CI = p \pm z \cdot \sqrt{\frac{p(1-p)}{n} } \\\\CI = 0.40 \pm 1.96 \cdot \sqrt{\frac{0.40(1-0.40)}{1000} } \\\\CI = 0.40 \pm 1.96 \cdot 0.01549 \\\\CI = 0.40 \pm 0.0304 \\\\CI = 0.40 - 0.0304 \: and \: 0.40 + 0.0304\\\\CI = (0.3696 ,\: 0.4304)$

Therefore, we are 95% confident that the proportion of consumers who bought the newest generation of mobile phone were happy with their purchase is within the range of (0.3696, 0.4304)

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.

3 0

3 years ago

HELP PLEASE!! ASAP!!!!

dezoksy [38]

Actions violated: