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rusak2 [61]
3 years ago
8

Drag each item to show if it is an element or not an element.

Engineering
1 answer:
Flauer [41]3 years ago
5 0

Answer:

CARBON

Explanation:

HOPE THIS HELPS SORRY FOR CAPS

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In the dataset "RestRating", the 30 randomly selected patrons give the overall dining experience ratings (Outstanding, Very good
rusak2 [61]

Answer: incomplete question

Explanation:

6 0
3 years ago
Read 2 more answers
Why are photopolymers essential for stereolithography?
Leokris [45]

Answer:

They essential for the formation of layers in a 3-D model.

Explanation:

Stereolithography is 3D printing process in which a 3D model can be created. In stereolithography technology, there is vat of the UV curable photopolymer which is placed below in lower compartment of machine.

<u>When the machine begins to construct 3D model by the scanning and the  building of one layer at one time. Each layer in the model is constructed with UV laser and as laser traces next layer of object material hardens on contact.  </u>

Once layer is complete, platform slips down to make room for next layer. This is how, a model is created.

5 0
3 years ago
A single crystal of zinc is oriented for a tensile test such that its slip plane normal makes an angle of 65 degree with the ten
Crank

Answer:

a. 30°

b. 0.9MPa

Explanation:

The slip will occur along that direction for which the Schmid factor is maximum. The three possible slip directions are mentioned as 30°, 48°, 78°

The cosines for the possible λ values are given as

For 30°, cos 30 = 0.867

For 48°, cos 48 = 0.67

For 78°, cos 78 = 0.21

Among the three-calculated cosine values, the largest cos(λ) gives the favored slip direction

The maximum value of Schmid factor is 0.87. Thus, the most favored slip direction is 30° with the tensile axis.

The plastic deformation begins at a tensile stress of 2.5MPa. Also, the value of the angle between the slip plane normal and the tensile axis is mentioned as 65°

Thus, calculate the value of critical resolved shear stress for zinc:

From the expression for Schmid’s law:

τ = σ*cos(Φ)*cos(λ)

Substituting 2.5MPa for σ, 30° for λ and 65° for Φ

We obtain The critical resolved shear stress for zinc, τ = 0.9 MPa

4 0
3 years ago
You are to design the control for an automatic candy vending machine. The candy bars inside the machine cost 25 cents, and the m
labwork [276]

Answer:

I believe that it is E. Write Verilog HDL models for the machine based on the state diagram in (a) and the D flip-flop sequential circuit that you implement in (b).

6 0
2 years ago
An aluminum electrical cable is 20 mm in diameter is covered by a plastic insulation (k = 1 W/m-k) of critical thickness. This w
Anastaziya [24]

Answer:

the heat loss from this insulated wire is less

Explanation:

Given data in question

diameter of cable (d)  =  20 mm

( K ) = 1 W/m-k

heat transfer coefficient (h) = 50 W/m²-K

To find out

the heat loss from this insulated wire

solution

we will find out thickness of wire

heat loss is depend on wire thickness also

we have given dia 20 mm

so radius will be d/2 = 20/ 2 = 10 mm

Now we find the critical thickness i.e.

critical thickness = K / heat transfer coefficient

critical thickness = 1 / 50 = 0.02 m i.e. 20 mm

now we can see that critical thickness is greater than radius 10 mm

so our rate of heat loss will be decreasing

so we can say our correct option is (a) less

5 0
3 years ago
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