Answer:
They essential for the formation of layers in a 3-D model.
Explanation:
Stereolithography is 3D printing process in which a 3D model can be created. In stereolithography technology, there is vat of the UV curable photopolymer which is placed below in lower compartment of machine.
<u>When the machine begins to construct 3D model by the scanning and the building of one layer at one time. Each layer in the model is constructed with UV laser and as laser traces next layer of object material hardens on contact. </u>
Once layer is complete, platform slips down to make room for next layer. This is how, a model is created.
Answer:
a. 30°
b. 0.9MPa
Explanation:
The slip will occur along that direction for which the Schmid factor is maximum. The three possible slip directions are mentioned as 30°, 48°, 78°
The cosines for the possible λ values are given as
For 30°, cos 30 = 0.867
For 48°, cos 48 = 0.67
For 78°, cos 78 = 0.21
Among the three-calculated cosine values, the largest cos(λ) gives the favored slip direction
The maximum value of Schmid factor is 0.87. Thus, the most favored slip direction is 30° with the tensile axis.
The plastic deformation begins at a tensile stress of 2.5MPa. Also, the value of the angle between the slip plane normal and the tensile axis is mentioned as 65°
Thus, calculate the value of critical resolved shear stress for zinc:
From the expression for Schmid’s law:
τ = σ*cos(Φ)*cos(λ)
Substituting 2.5MPa for σ, 30° for λ and 65° for Φ
We obtain The critical resolved shear stress for zinc, τ = 0.9 MPa
Answer:
I believe that it is E. Write Verilog HDL models for the machine based on the state diagram in (a) and the D flip-flop sequential circuit that you implement in (b).
Answer:
the heat loss from this insulated wire is less
Explanation:
Given data in question
diameter of cable (d) = 20 mm
( K ) = 1 W/m-k
heat transfer coefficient (h) = 50 W/m²-K
To find out
the heat loss from this insulated wire
solution
we will find out thickness of wire
heat loss is depend on wire thickness also
we have given dia 20 mm
so radius will be d/2 = 20/ 2 = 10 mm
Now we find the critical thickness i.e.
critical thickness = K / heat transfer coefficient
critical thickness = 1 / 50 = 0.02 m i.e. 20 mm
now we can see that critical thickness is greater than radius 10 mm
so our rate of heat loss will be decreasing
so we can say our correct option is (a) less